Hello!
Since we already see an equation that equals y (-2x-4), we can plug that equation into the first to solve for x.
x+4(-2x-4)=19
x-8x-16=19
-7x=35
x=-5
Now that we know the value of x, we will plug it into the second equation to solve for y.
y=-2(-5)-4
y=10=4
y=6
This gives us the answer below
The correct answer is A) (-5,6)
I hope this helps!
Answer:
it's D. I think 105 cubic feet
Yes; you are correct.
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The correct answer is:
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Answer choice: [C]: " x³ − 9x² + 23x <span>− 12 " .
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Note: (a </span>− b) (c − d + e) = ac − ad + ae − bc + bd − be ;
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(x − 4) (x² <span>− 5x + 3) =
x * x</span>² = x³ <span>−
x * 5x = 5x</span>² +
x * 3 = 3x <span>−
4 * x</span>² = 4x² <span>−
-4 * 5x = -20x +
-4 * 3 = -12;
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</span> (x − 4) (x² − 5x + 3) =
x³ − 5x² + 3x −4x² − (-20x) + (-12) ;
= x³ − 5x² + 3x −4x² + 20x − 12 ;
= x³ − 5x² − 4x² + 3x + 20x − 12 ;
= x³ − 9x² + 23x − 12 ; which is:
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Answer choice: [C]: " x³ − 9x² + 23x − 12 " .
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Answer:
A. y = 1/2 x
Step-by-step explanation:
A proportional relationship between two quantities is a collection of equivalent ratios, related to each other by a constant of proportionality. In other words, if each point on the line can be put as a fraction and reduced to the same fraction, the relationship is proportional.
The answer is (3600 - 900π) ft²
Step 1. Find the radius r of circles.
Step 2. Find the area of the portion of the field that will be watered by the sprinklers (A1)
Step 3. Find the total area of the field (A2)
Step 4. Find the area of the portion of the field that will not be watered by the sprinklers (A)
Step 1. Find the radius r of circles
r = ?
According to the image, radius of a square is one fourth of the field side length:
r = s/4
s = 60 ft
r = 60/4 = 15 ft
Step 2. Find the area of the portion of the field that will be watered by the sprinklers.
The area of the field that will be watered by the sprinklers (A1) is actually total area of 4 circles with radius 15 ft.
Since the area of a circle is π r², then A1 is:
A1 = 4 * π r² = 4 * π * 15² = 900π ft²
Step 3. Find the total area of the field (A2)
The field is actually a square with side s = 60 ft.
A2 = s² = 60² = 3600 ft²
Step 4. Find the area of the portion of the field that will not be watered by the sprinklers (A).
To get the area of the portion of the field that will not be watered by the sprinklers (A) we need to subtract the area of 4 circles from the total area:
A = A2 - A1
A = (3600 - 900π) ft²
