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3 years ago

PLEASE ANSWER URGENT WILL GIVE BRAINLIEST AND 20 POINTS.

Mathematics

1 answer:

Butoxors [25]3 years ago

6 0

C $~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~$

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Need some help with multiplying algebraic fractions

Nezavi [6.7K]

Answer:

a=10, b=5, c=2, d=12

Step-by-step explanation:

Multiply each variable together

5*2=10

8*3=24

10 $x^{3}$ $y^{2}$ /24x

the coefficients (numbers) can each be divided by 2

5 $x^{3} y^{2}$ /12x

subtract the "x" exponents together

5 $x^{2} y^{2}$ /12

8 0

3 years ago

the length of an arc of a circle is 269⁢πcentimeters and the measure of the corresponding central angle is 65∘. what is the leng

scZoUnD [109]

The length of the circle's radius = 744.92 cm

Given the length of arc of a circle, arc length = 269⁢π cm

Central angle of a circle is the angle made between the radius through the arc length at the center of the circle.

The corresponding central angle = 65°

To find the corresponding central angle in radians = 65° x π/180 = 13π/36 radians

We have, arc length of a circle = radius x central angle

Therefore, radius of the circle = arc length / central angle

= 269⁢π /(13π/36)

= 744.92 cm

Learn more about arc length of a circle at brainly.com/question/28108430

#SPJ4

6 0

2 years ago

At a school event there were 96 girls .the ratio of number of girls to the number of boys was 4:5

valina [46]

144, 4:6 simplifies to 2:3, if you divide 96 by 2 you get 48, and 48 x 3 = 144

8 0

4 years ago

7 yards and 2 feet is equal to how many feet

alisha [4.7K]

<span>7 yards 2 feet = 23 feet
</span>

3 0

3 years ago

Read 2 more answers

An isosceles triangle has a perimeter of 18 cm. Find a function that models its area A in terms of the length of its base b.

IgorLugansk [536]

So.... notice the picture below

now, we know what the "height" or "altitude" is
now, we also know the perimeter is 18cm

so, k + k + b = 18
or 2k + b = 18
thus $\bf k=\cfrac{18-b}{2}$

so... one can say that $\bf \textit{area of a triangle}=A=\cfrac{1}{2}bh\qquad 
\begin{cases}
b=b
\\\\
h=\sqrt{k^2-\left( \frac{b}{2} \right)^2}
\\\\
h=\sqrt{k^2-\frac{b^2}{4}}\\
--------------\\
k=\frac{18-b}{2}\qquad thus\\
--------------\\
h=\sqrt{\left( \frac{18-b}{2} \right)^2-\frac{b^2}{4}}
\end{cases}\\\\
-----------------------------\\\\
A=\cfrac{1}{2}\cdot b\cdot \sqrt{\left( \frac{18-b}{2} \right)^2-\frac{b^2}{4}}$

and you can simplify it if you wish.. not sure you have to

7 0

3 years ago