8/15 or somthing like that it you might be souposed to solve it diferent than i did
Answer:
The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft
Step-by-step explanation:
Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²
For maximum volume, the side length, s of the cube must all be equal ;
Therefore area of one side = s²
Number of sides in a cube with top open = 5 sides
Area of surface = 5 × s² = 180
Therefore s² = 180/5 = 36
s² = 36
s = √36 = 6 ft
Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.
The volume of one box is 240 inches cubed, because 12x8x2.5=240. If we multiply this by 2, then the volume of two boxes of detergent is 480 inches cubed.
56/90
" / " means divide
56 divided by 90 = 0.62 with a line over the 2 because it is repeating
Answer: 158 as area and perimeter 62
Step-by-step explanation:
