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3 years ago

Which group scope can be used to assign permissions to resources only in the domain in which the group is created

Computers and Technology

1 answer:

sleet_krkn [62]3 years ago

8 0

Answer: Domain local group

Explanation:

Domain Local Group is a form of group in a Windows Server network in Microsoft which is used by an administrator to assign permissions to the resources that are in same domain.

Their scope is strictly restricted to their particular domain. It should also be noted that they've open membership which simply implies that members form other domain can be added to them. One has to first know the users that have identical job responsibilities in order to use the domain local group, then identify the network resources that are similar which users want to access.

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Give five examples of physical networking.

Vika [28.1K]

Answer:

Local area network (LAN), Wide area network (WAN), Metropolitan area network (MAN), Personal area network (PAN), Others

Explanation:

Others can be classified as peer to peer, bluetooth

6 0

3 years ago

Anyone willing to help with Excel?!!

anastassius [24]

Hi!

I have a slight understanding of excel, it depends on what you need.

8 0

3 years ago

In C Coding, print either "Fruit", "Drink", or "Unknown" (followed by a newline) depending on the value of userItem. Print "Unkn

shutvik [7]

The code below uses if-else structure to print the output depending on the value of the userItem.

If the specified condition in the if structure is true, the block in the structure gets executed.

Comments are used to explain the each line of the code.

//main.c

#include <stdio.h>

int main()

{

//defining the enum and userItem

enum GroceryItem {GR_APPLES, GR_BANANAS, GR_JUICE, GR_WATER};

enum GroceryItem userItem;

//initializing the userItem

userItem = GR_APPLES;

//checking the userItem

//If it is GR_APPLES or GR_BANANAS, print "Fruit"

//If it is GR_JUICE or GR_WATER, print "Drink"

//Otherwise, print "Unknown"

if(userItem == GR_APPLES || userItem == GR_BANANAS){

printf("%s\n", "Fruit");

}

else if(userItem == GR_JUICE || userItem == GR_WATER){

printf("%s\n", "Drink");

}

else{

printf("%s\n", "Unknown");

}

return 0;

}

You can see a similar question at:

brainly.com/question/17592042

6 0

3 years ago

Please explain this code line by line and how the values of each variable changes as you go down the code.

Scilla [17]

Answer:

hope this helps. I am also a learner like you. Please cross check my explanation.

Explanation:

#include

using namespace std;

int main()

{

int a[ ] = {0, 0, 0}; //array declared initializing a0=0, a1=0, a3=0

int* p = &a[1]; //pointer p is initialized it will be holding the address of a1 which means when p will be called it will point to whatever is present at the address a1, right now it hold 0.

int* q = &a[0]; //pointer q is initialized it will be holding the address of a0 which means when q will be called it will point to whatever is present at the address a0, right now it hold 0.

q=p; // now q is also pointing towards what p is pointing both holds the same address that is &a[1]

*q=1 ; //&a[0] gets overwritten and now pointer q has integer 1......i am not sure abut this one

p = a; //p is now holding address of complete array a

*p=1; // a gets overwritten and now pointer q has integer 1......i am not sure abut this one

int*& r = p; //not sure

int** s = &q; s is a double pointer means it has more capacity of storage than single pointer and is now holding address of q

r = *s + 1; //not sure

s= &r; //explained above

**s = 1; //explained above

return 0;

}

6 0

3 years ago

Write a recursive function, displayFiles, that expects a pathname as an argument. The path name can be either the name of a file

Virty [35]

The following code will be used to write a recursive function and display files

<u>Explanation:</u>

#Import required packages

import os

#Define recursive function

#displayFiles() has a single argument

#which may be either pathname or filename

def displayFiles(pathname):

#if the given argument is pathname for directory

if (os.path.isdir(pathname)):

#open the directory

for item in os.listdir(pathname):

#append items in the list

newItem = os.path.join(pathname, item)

#print each filename

#call the function recursively

displayFiles(newItem)

#otherwise if the pathname

#is filename

else:

#set the pathname to filename

filename=pathname

baseFile = os.path.basename(filename)

print("File Name: ", baseFile)

#open the file in read mode

with open(filename, "r") as file:

print("Content:")

#display the contents of the file

for line in file:

#print line

print(line)

print()

8 0

3 years ago