I really need some help so pls someone help me

PLZ HELP ME I REALLY NEED HELP

Setler79 [48]

I got the last one there are 40,000 worker bees living in one hive

I just got to get the mass of

3 0

4 years ago

Read 2 more answers

The population of a coty is 100,000 and the annual growth rate is 4.2%. Write an equation to model the population y after x year

Andrews [41]

Answer: $1,00,000(1+0.042)^x$

Step-by-step explanation:

Given

The initial population of a city is $P_o=1,00,000$

The annual growth rate is $4.2\%$

after 1 year it is

$\Rightarrow P_1=1,00,000+4.2\%\times 1,00,000\\\Rightarrow P_1=1,00,000(1+0.042)$

after 2 years, it is

$\Rightarrow 1,00,000(1+0.042)+4.2\%\times 1,00,000(1+0.042)\\\Rightarrow 1,00,000(1+0.042)^2$

after x years it is

$\Rightarrow P_x=1,00,000(1+0.042)^x$

5 0

3 years ago

This week, we are covering relationships that can be approximated by linear equations. For instance, y = 453x + 3768 represents

lana [24]

Answer:

See explanation below.

Step-by-step explanation:

We assume that the data is given by :

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

Where X represent the cost for scholarships in thousands of dollars and y represent the cost of life for an academic semester (The data comes from the web)

We can find the least-squares line appropriate for this data.

For this case we need to calculate the slope with the following formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

So we can find the sums like this:

$\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720$

$\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324$

$\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200$

$\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540$

$\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=17540-\frac{720*324}{12}{12}=-1900$

And the slope would be:

$m=-\frac{1900}{6000}=-0.317$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60$

$\bar y= \frac{\sum y_i}{n}=\frac{324}{12}=27$

And we can find the intercept using this:

$b=\bar y -m \bar x=27-(-0.317*60)=46.02$

So the line would be given by:

$y=-0.317 x +46.02$

We have an inverse linear relationship since the slope is negative between the variables of interest.

8 0

4 years ago

Which of the following is the equation of a line that passes through the points (1,6) and(2,1)

Alisiya [41]

Answer:

y=1x-5

Step-by-step explanation:

it goes over to the right 1 time and down 5

(1+1,6-5)=(2,1)

8 0

3 years ago

Mitch completes the course and his boss promotes him. Mitch receives a 25% increase on his previous pay of $40 000 per year afte

kolezko [41]

Before her promotion, Mitch was receiving $40,000 per year after tax. Since the loan payment is 4%, therefore the money that goes to the loan is:

Loan payment = $40,000 * 0.04

Loan payment = $1,600

After her promotion, Mitch is now receiving:

New salary = $40,000 * 1.25

New salary = $50,000

Therefore the new loan payment becomes:

New loan payment = $50,000 * 0.04

New loan payment = $2,000

Therefore Mitch is paying an extra payment of:

$2,000 - $1,600 = $400

Answer: $400

4 0

3 years ago