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ASHA 777 [7]
3 years ago
10

Find the next two terms for the following pattern 1, -2, 2, -4, 0

Mathematics
1 answer:
Oxana [17]3 years ago
5 0
After figuring out a common difference in this pattern, we can get further terms in the pattern:
1, -2, 2, -4, 0, -3, -1
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2(1 – 8x) = 1/2 (8 - 64x)​
faust18 [17]

Answer:

x=\frac{1}{8}

Step-by-step explanation:

A quick review on PEMDAS, the order of how to solve an equation:

P - parentheses. When parentheses are being used, you have to do everything inside them before doing everything outside of them.

E - exponents. We'll skip these, since there aren't any exponents we need to worry about in this equation.

M/D - multiplication/division. I include these both together because they can be done at the same time.

A/S = addition/subtraction. Can also be done at the same time.

Some other things to note:

You add all the things with an x attached to it, and you add all the things without an x attached to it, and these never cross.

When you bring something from one side of an equal sign to another, you make it negative.

Let's solve for x using what we've learned:

2(1-8x)=\frac{1}{2} (8-64x)\\2-16x=4-32x\\16x=2\\x=\frac{2}{16} \\x=\frac{1}{8}

8 0
3 years ago
An object is launched with a velocity at 64 feet per second from a platform 30 feet high. the function H(t)= -16t2+64t+30 repres
PolarNik [594]
To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.

H'(t) = -32t + 64

Now find the critical numbers:

-32t + 64 = 0

-32t = -64

t = 2 seconds

Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):

H'(1) = 32

H'(3) = -32

As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.

To find the height, plug t=2 into H(t):

H(2) = -16(2)^2 +64(2) + 30 = 94

The answer is 94 ft at 2 sec.
4 0
3 years ago
Find the missing dimension of each prism: volume= 56 1/4 ft | width= 3 3/4 ft | length= 7 1/2 ft
Juliette [100K]
Prism volume = width*length*height
56 1/4 = 3 3/4 * 7 1/2 * h

56.25=3.75*7.5*h

h=(56.25)/(3.75*7.5)=2

So that the missing dimension (height) is 2 ft

4 0
4 years ago
Help me on 8 and 9 plz
klasskru [66]
8. first 12 bags for 54m^{2} [/tex]  
 54 ÷ 12 = 4.5
we know: 1 bag for 4.5m^2
36 ÷ 4.5 = 8
so 36m^2 we must use 8 bags

9. \frac{5}{8}x2 =5x2/8= 10/8 = 5/4 = 1.25

 hope it helped you
5 0
3 years ago
The center of the circle is at (-2,-7) and its radius is 36.
Vanyuwa [196]
Standard form for circle with radius r and center (h,k) is
(x-h)^2+(y-k)^2=r^2

r=36
center at -2,-7
(x-(-2))^2+(y-(-7))^2=36^2
(x+2)^2+(y+7)^2=1296


firts option
6 0
3 years ago
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