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nikitadnepr [17]
3 years ago
13

Question and answer in image

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
3 0

Answer:

46

Step-by-step explanation:

2 *radius

So is 2*23 then you will get 46 ft.

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Question 2 4 The Triangle Sum Theorem is used to determine if the angles from two triangles are similar? True Or False ​
saveliy_v [14]

Answer:

Fasle it is used to deturme a missing angle's deggres.

4 0
4 years ago
Write a real world problem where you would have to multiply 120 and 75
LekaFEV [45]
I made $120 a week. How much money would I be able to make in 75 weeks?

120 x 75 = 1040

I would make $1040 in 75 weeks. 

Hope this was ok enough. :)
3 0
4 years ago
Read 2 more answers
A chain has a ribbon tied to it every 2/3 foot. If the chain is 10 2/3 feet long, how many ribbons are tied to the chain??
patriot [66]

Answer:

16 ribbons

Step-by-step explanation:

Given the length of the chain as 10\frac{2}{3} and there is a ribbon tied to it every \frac{2}{3}, we can take the total length of the chain and divide by the measure of \frac{2}{3}:

10\frac{2}{3}=\frac{32}{3}

\frac{\frac{32}{3}}{\frac{2}{3}}=\frac{32}{3}*\frac{3}{2}=\frac{96}{6}=16

When dividing with fractions, we use the rule of 'keep/change/flip' to keep the first fractions, change the operation to multiplication and flip the second fraction.  

7 0
3 years ago
Help !! (x + 2y = 6.)
Dominik [7]

Answer:

what do you exactly want me to do? rewrite the equation or solve it?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl
lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

m=\frac{y_2-y_1}{x_2-x_1 }

<u>Slope  of AB</u>

m_{AB}=\frac{8-5}{1--5}

\Rightarrow m_{AB}=\frac{8-5}{1+5}

\Rightarrow m_{AB}=\frac{3}{6}

\Rightarrow m_{AB}=\frac{1}{2}


<u>Slope of BC</u>

m_{BC}=\frac{2-8}{4-1}

\Rightarrow m_{BC}=\frac{-6}{3}

\Rightarrow m_{BC}=-2

<u>Slope of CD</u>

m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-4}{-6}

\Rightarrow m_{CD}=\frac{2}{3}

<u>Slope of AD</u>

m_{AD}=\frac{-2-5}{-2--5}

\Rightarrow m_{AD}=\frac{-2-5}{-2+5}

\Rightarrow m_{AD}=\frac{-7}{3}

<u>Verify Parallel sides</u>

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

m_{AD} = \frac{-7}{3} \neq m_{BC}=-2

m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}


<u>Verify Perpendicularity</u>

And also the product of slopes of all sides with a common vertex should be -1. But

m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1

m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1


Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle




6 0
3 years ago
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