All categories

2 years ago

C. If a < 0 and f(a) > 0, then the point (a, f(a))

1 answer:

3 0

The answer is: b - lies in quadrant II when graphed.

Explanation:

Any number less than zero is a negative number.

Example: -1

Any number greater than zero is a positive number.

Example: 1

(a, f(a))

(-1,1)

When these example points are graphed, they are placed in the second quadrant.

You might be interested in

A long-distance athlete can run 1212 kilometer in 3 minutes. How many kilometers can he run in an hour?

Mrrafil [7]

1212 km in 3 min
3min • 20= 60 min = 1 hour
1212km • 20 = 24, 240km

8 0

3 years ago

How do you translate a polygon on a graph?

Usimov [2.4K]

You draw a polygon on the graph

8 0

1 year ago

9. Max walks 2 km to school in 40 minutes and Dave cycles 5 km to school in 15

Alona [7]

Max’s distance : Dave’s distance = 2 km : 5 km = 2:5
Max’s time : Dave’s time = 40 min : 15 min = 40:15 = 8:3

5 0

2 years ago

Read 2 more answers

Can someone please help me

defon

9514 1404 393

Answer:

P = 50,000

r = 0.08

i = 0.02

K = 4

n = 20

t = 5

Step-by-step explanation:

In this formula, r is the annual interest rate, 8% or 0.08. K is the number of times the interest is compounded in a year. Since interest is compounded quarterly, K = 4.

r = 0.08

i = r/K = 0.08/4

i = 0.02

t is the number of years interest is compounded, so ...

t = 5

n = Kt = 4·5

n = 20

P is the principal amount invested:

P = 50,000

7 0

2 years ago

Precalc.

viktelen [127]

Domain: x>0.

$(\log_2x)^2+7\log_2x+12=0$

Substitute $t=\log_2x\in\mathbb{R}$ . We have:

$t^2+7t+12=0\\\\a=1\qquad b=7\qquad c=12\\\\\\\Delta=b^2-4ac=7^2-4\cdot1\cdot12=49-48=1\\\\\sqrt{\Delta}=\sqrt{1}=1\\\\\\
t_1=\dfrac{-b-\sqrt{\Delta}}{2a}=\dfrac{-7-1}{2}=\dfrac{-8}{2}=-4\\\\\\
t_2=\dfrac{-b+\sqrt{\Delta}}{2a}=\dfrac{-7+1}{2}=\dfrac{-6}{2}=-3$

For t₁ there will be:

$\log_2x=t_1\\\\\log_2x=-4\\\\2^{-4}=x\\\\x=\dfrac{1}{2^4}\\\\\\x=\dfrac{1}{16}=0,0625\\\\\\\boxed{x\approx0,063}$

and for t₂:

$\log_2x=t_2\\\\\log_2x=-3\\\\2^{-3}=x\\\\x=\dfrac{1}{2^3}\\\\\\x=\dfrac{1}{8}\\\\\\\boxed{x=0,125}$

Answer d)

6 0

3 years ago