Given:
A fourth-degree polynomial function has zeros 4, -4, 4i , and -4i .
To find:
The fourth-degree polynomial function in factored form.
Solution:
The factor for of nth degree polynomial is:
Where, 
are n zeros of the polynomial.
It is given that a fourth-degree polynomial function has zeros 4, -4, 4i , and -4i. So, the factor form of given polynomial is:
![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
On further simplification, we get
![[\because i^2=-1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20i%5E2%3D-1%5D)
Therefore, the required fourth degree polynomial is .
Answer:
keep calm and believe in yourself
Answer:
y = 8x + 4
Step-by-step explanation:
y=mx+b
m=8
y = 8x + b
We just need to find b. B is where the line intersects the y- axis. On the y-axis by definition, the x-coordinate =0 but that is not helpful now...
Let's re write and try to solve for b. That means write as b = ...
y = 8x + b
b = y - (8x)
Substitute for x and y the numbers of the coordinates of the given point (3,28):
b = y - (8*x)
b = 28 - (8*3)
b = 28 - 24
b = 4
So the answer is y = 8x + 4
The double of 50 is 100 which means you would do 28*100=2800 now half of the answer is 2800/2=1400 which makes 1,400 your answer
