Use the formula h(t) = -16t^2 + vt + s,
where t = time in air,
v = starting upward velocity,
s = the objects starting height.
from ground (s), the starting height is 0,
the ball's initial velocity (v) 25 feet per second
Solve:
v - 16t^2 + (25)t + 0
= -16t^2 + 25t. 0
Factor:
= -16t^2 + 25t
Find GCF:
0 = -16t^2 + 25t
Divide both sides by (t)
t(-16 + 25) = 0
t = 0; -16 + 25 = 0
Now Subtract 25 from both sides of equation:
-16 = -25
divide both sides by -16 to get -25/-16
= 1.56
Rounds to 1.60, or 1.6
Answer: 1.6 Seconds it will take for soccer ball to hit the ground again.
First part of the Equation: Answer: 9.8Ft. Soccer ball will reach at maximum height.
Hope that helps!!!! : )
Answer:
The lower bound of a 99% C.I for the proportion of defectives = 0.422
Step-by-step explanation:
From the given information:
The point estimate = sample proportion 
= 0.55
At Confidence interval of 99%, the level of significance = 1 - 0.99
= 0.01
Then the margin of error 
E = 0.128156
E ≅ 0.128
At 99% C.I for the population proportion p is: 
= 0.55 - 0.128
= 0.422
Thus, the lower bound of a 99% C.I for the proportion of defectives = 0.422
Answer:
in this case you can use protector also but
there is another way
Step-by-step explanation:
as we know sum of a triangle is 180 degree
so let's D= 2x,x
35+x+2x=180
3x+35=180
3x=180-35
3x=145
x=145÷3
x =46.06
