X²+10x+21=0
/\ = 10²-4*1*21
/\ = 100 - 84
/\ = 16
x = (-10+/-\/16)/2
x = (-10+/-4)/2
x' = (-10+4)/2 = -6/2 = -3
x" = (-10-4)/2 = -14/2 = -7
S: {-3; -7}
Answer:
∠B =
Step-by-step explanation:
Given : a=7 b=10 and C is a right triangle
solution :
refer the attached figure .
Since ΔACB is right angled triangle so we will use trigonometric ratios .

Perpendicular = b =10
Base=a=7
Putting value in formula:




Thus ∠B =
Answer:
4.5 x 2
Step-by-step explanation:
4.5 x 2 = 9
Hope it helps
It moves the line on the X axis to a different spot when moved
hope this helps <span />