Answer :
Option A) 2.00 eV
Explanation : The conversion of J to eV is done with the following formula;
Here, we have the value of particle in terms of Joules which is 3.2 X
So, on substituting we get,
= 3.2 X
X
= 1.99 eV so, it can be rounded off to 2.00 eV.
<span>2NaCN + (1)H2SO4 → Na2SO4 + 2HCN
</span><span>The coefficient of sulfuric acid is 1.</span>
We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+ + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
z= 4.81x10^-7
∴[H+] = 4.81x10^-7
when PH equation is:
PH= -㏒[H+]
= -㏒(4.81x10^-7) = 6.32
When a bond is broken that should be a type of reaction. When bonds are broken sometimes heat is released.
The answer is d, hand soap.
Hand soap is alkaline and red litmus paper turns blue when exposed to alkaline solution.
