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mote1985 [20]
3 years ago
15

Who is credited with creating the first accurate model of DNA

Chemistry
2 answers:
Temka [501]3 years ago
7 0

Answer:James Watson and Francis Crick are credited with creating first accurate model of DNA.

Explanation:

kupik [55]3 years ago
7 0

Answer:

Watson & Crick.

Explanation:

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Need the following questions answered please and thank you
Ket [755]
Hope this might help u

6 0
2 years ago
How many grams of P2Cl5 are produced if 2.00 moles of P reacts with an excess of Cl2?
Roman55 [17]

Answer:

m_{P_2Cl_5 }=239.2125gP_2Cl_5

Explanation:

Hello there!

In this case, according to the reaction:

4P+5Cl_2\rightarrow 2P_2Cl_5

Thus, since there is a 4:2 mole ratio of P to P2Cl5 and the molar mass of the later is 239.2125 g/mol, we obtain the following mass as the produced one:

m_{P_2Cl_5 }=2.00molP*\frac{2molP_2Cl_5}{4molP} *\frac{239.2125gP_2Cl_5 }{1molP_2Cl_5} \\\\m_{P_2Cl_5 }=239.2125gP_2Cl_5

Regards!

5 0
3 years ago
Fireworks exploding in the sky and giving off light are an example of a(n) _____.
Serggg [28]
Exothermic change. Because the firework when it exploded, released energy in the form of light. In exothermic changes energy is released, and in endothermic changes energy is absorbed.

- This wouldn't be a physical change, but instead a chemical change. A clue that it is a chemical change is that energy was given off.
7 0
3 years ago
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What is a kilogram??
sukhopar [10]

A kilogram is a measure of mass; 1,000 grams

8 0
3 years ago
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A compound that is composed of molybdenum (Mo) and oxygen (O) was produced in a lab by heating molybdenum over a Bunsen burner.
irakobra [83]
First, we determine the mass of each element from the data collected. We can get the mass of molybdenum Mo from the difference between the mass of crucible and molybdenum and the mass of crucible:
     Mass of molybdenum = 39.52 – 38.26 = 1.26 g Mo

We can calculate for the mass of molybdenum oxide from the difference between the mass of crucible and molybdenum oxide and the mass of crucible:
     Mass of molybdenum oxide = 39.84 – 38.26 = 1.58g 

We can now compute for the mass of oxygen O by subtracting the mass of molybdenum from the mass of molybdenum oxide:
     Mass of oxygen in molybdenum oxide = 1.58 – 1.26 = 0.32g O

To convert mass to moles, we use the molar mass of each element.
     1.26 g Mo * 1 mol Mo / 95.94 g Mo = 0.0131 mol Mo
     0.32 g O * 1 mol O / 15.999 g O = 0.0200 mol O

0.0131 mol is the smallest number of moles. We divide each mole value by this number:
     0.0131 mol Mo / 0.0131 = 1
     0.0200 mol O / 0.0131 = 1.53

Multiplying these results by 2 to get the lowest whole number ratio,
     0.0131 mol Mo / 0.0131 = 1 * 2 = 2
     0.0200 mol O / 0.0131 = 1.5 * 2 = 3
Thus, we can write the empirical formula as Mo2O3.
5 0
3 years ago
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