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worty [1.4K]
3 years ago
10

A common laboratory method for preparing a precipitate is to mix solutions containing the component ions. Does a precipitate for

m when 10. ml of 0.0010 M Ca(NO3)2 is mixed with 10. ml of 0.00010 M NaF? Ksp for CaF2 = 3.2 x 10-11
Chemistry
1 answer:
laiz [17]3 years ago
5 0

Answer:

CaF2 will not precipitate

Explanation:

Given

Volume of Ca(NO3)2 = 10 ml

Molar concentration of Ca(NO3)2 = 0.001

Volume of NaF = 10 ml

Molar concentration of  NaF  = 0.0001

Ksp for CaF2 = 3.2 * 10^ {-11}

CaF2 will precipitate if Q for the reaction is greater than ksp of CAF2

Moles of calcium ion

= 10 * 0.001\\= 0.01

[Ca2+] = \frac{0.01}{10 + 10} \\= \frac{0.01}{20} \\= 5 * 10^{-4}

Moles of F- ion

= 10 * 0.0001\\= 0.001

[F-] = \frac{0.001}{10 + 10} \\= \frac{0.001}{20} \\= 5 * 10^{-5}

Q = [Ca2+] [F-]^2\\= (5 * 10^{-4}) * (0.5* 10^-4)\\= 1.25 * 10^{-12}

Q is lesser than Ksp value of CaF2. Hence it will not precipitate

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A chemical bond is formed between magnesium and chlorine. Describe the process and identify the nature of the chemical bond.
IRINA_888 [86]

Answer:

The answer to your question is: b

Explanation:

a. Magnesium shares an electron somewhat unevenly from its 3s orbital with the 3p orbital of chlorine producing a mildly polar covalent bond.  This option is wrong because Mg does not share electrons it loses electrons.

b. Magnesium loses and electron from the 3s and gives it up to the 3p of chlorine producing an ionic bond.  This option is correct, Mg loses one electron and Cl receives it, the bond formed between Mg and Cl is ionic.

c. Magnesium does not react chemically with chlorine because magnesium gives up electrons, but chlorine only shares electrons.  This answer is wrong, Mg and Cl react and produce MgCl₂.

d. Magnesium shares an electron from the 3s orbital with the 3p orbital of chlorine producing a covalent bond. Mg does not share electrons and is not able to produce covalent bonds.

7 0
3 years ago
A student does an experiment to determine the molar solubility of lead(II) bromide. She constructs a voltaic cell at 298 K consi
attashe74 [19]

Answer:

The molar solubility of lead bromide at 298K is 0.010 mol/L.

Explanation:

In order to solve this problem, we need to use the Nernst Equaiton:

E = E^{o} - \frac{0.0591}{n} log\frac{[ox]}{[red]}

E is the cell potential at a certain instant, E⁰ is the cell potential, n is the number of electrons involved in the redox reaction, [ox] is the concentration of the oxidated specie and [red] is the concentration of the reduced specie.

At equilibrium, E = 0, therefore:

E^{o}  = \frac{0.0591}{n} log \frac{[ox]}{[red]} \\\\log \frac{[ox]}{[red]} = \frac{nE^{o} }{0.0591} \\\\log[red] =  log[ox] -  \frac{nE^{o} }{0.0591}\\\\[red] = 10^{ log[ox] -  \frac{nE^{o} }{0.0591}} \\\\[red] = 10^{ log0.733 -  \frac{2x5.45x10^{-2}  }{0.0591}}\\\\

[red] = 0.010 M

The reduction will happen in the anode, therefore, the concentration of the reduced specie is equivalent to the molar solubility of lead bromide.

7 0
3 years ago
Mass = 200.0 g volume = 100.0cm3 What is the density?
Marianna [84]
The density of an object is defined as its mass divided by its volume. Mathematically, density = Mass / Volume. The unit of density is kilogram per cubic meter, kg / m^3 or g /cm^3.
For the question given above: the 
Mass = 200.0 g
Volume = 100.0 cm^3
Therefore, Density = Mass / Volume = 200 / 100  = 2
Thus,  the density of the object is 2 g /cm^3.
3 0
3 years ago
When we have stomach disorders, we take antacids to solve the problem? how does it help? support your answer with an equation.
Sedbober [7]

Answer:

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Explanation:

Antacid contains ingredients such as aluminum, calcium, magnesium and sodium bicarbonate which act as bases. These help neutralise the pH levels in the stomach and makes the contents of the stomach less corrosive.

4 0
3 years ago
You want to determine the concentration of a solid solute dissolved in a specified volume of liquid solvent which of the followi
Natali [406]
Generally, chemists prefer to use morality (B) because it only invovles measuring the final volume of the solution and amount of moles of the solute

Hope this helps
6 0
3 years ago
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