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kipiarov [429]
3 years ago
10

PLEASE HELPP!

Mathematics
1 answer:
zheka24 [161]3 years ago
7 0

Answer:

5^2 = 100

100 x 3.14 = 314

Now we multiply by 20 since it's the height.

314 x 20 = 6,280 cm^3 is your answer.

Formula of cylinder:

H x πr^2

Height x pi(3.14 or 22/7 depending what they tell you to use for pi) x radius being squared (your radius is half of your diameter or given radius).

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State the system of linear inequalities which satisfies the following shaded regions. help ??asappp
7nadin3 [17]

Find the equation of the line that does not have an equation written for it.

(4, -4) (0,-2)

m = (-2 + 4) / (0 - 4)

m = 2 / -4  = -1/2

y = -1/2x - 2

Let's now look at all of these different lines we have. For the two intersecting lines, we know that the bottom one must be greater than and the top must be less than. And because these are solid lines, they are greater/less than or equal to. For the dotted line, we know that x must be less than because the line is dotted and the shading is to the left.

y ≤ x - 2

x < 4

y ≥ -1/2x - 2

Hope this helps! :)

6 0
3 years ago
On a piece of paper, use a protractor and a ruler to construct △ABC with AB=4 in., AC=4 in., and m∠A=60°.
ollegr [7]

Answer:

BC 4 in

Step-by-step explanation:

The steps for construction;

  • Using a ruler draw line AB 4 inches  and label the end points A and B
  • At point A , using a protractor, measure angle 60° and mark with point. Draw a line from A passing through this point extending to a length of 4 inches
  • Mark that point C.
  • Using the ruler, join point C and B and measure BC.

From calculation, length BC can be found by the formula;

BC=\sqrt{a^2+b^2-2*a*b*cosA}------where a=b=4 in , cos A = cos 60°

BC=\sqrt{4^2+4^2-2*4*4*cos60}

BC = 4 in

6 0
3 years ago
Read 2 more answers
Will mark brainliest if your are correct!
zavuch27 [327]

Answer:

20.1

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Part a how many inches would a point on the outer edge of the large gear travel in a 150º rotation?
Rasek [7]

Approximately 20.47 inches

<h3>How to calculate the value?</h3>

given large central gear radius r = 4 inches.

small central gear radius = 2 inches.

if large gear travel in a 150º rotation distance travelled by large gear is

\frac{150 {}^{0} }{360 {}^{0} } \times 2 \times \pi \times 4  \\  \frac{10}{3}  \times \pi \\ 10.47 \: inches

so, distance travelled by outer edge is 10.47 inches.

Learn more about gear transmission,refer

brainly.com/question/3926797

#SPJ4

Disclaimer : This question was incomplete in potal.Here is the complete question

Question: The gear is one of the oldest mechanical devices. It has been used since ancient times for its ability to increase or decrease rotational velocity. When one gear turns another, the outer portions of the gears are turning at the same linear speed. However, when one gear is smaller or larger than the other, the speed of rotation will be different for each gear.

Let’s look at an application of gears that you’ve seen before. On a bicycle, the pedals are attached to a large gear at the center of the bike, and a chain connects the large gear to a small gear attached to the rear wheel. The chain does not change the speed of rotation; it serves only to separate the centers of rotation.

Consider a bicycle where the large central gear has a radius of 4 inches and the small back gear has a radius of 2 inches.

Part A : How many inches would a point on the outer edge of the large gear travel in a 150º rotation?

3 0
2 years ago
I’m not understanding this question at all. WILL GIVE BRAINLY!! (6 is not the answer)
IRISSAK [1]

Answer:

-8.

Step-by-step explanation:

Substitute BC with the -4 and 2, as you were given those values to substitute with B and C. Multiply those two values. You get -8.

7 0
3 years ago
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