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jolli1 [7]
3 years ago
13

The area of the triangle is 44 inches. The height of the triangle is 11 inches what is the base?

Mathematics
1 answer:
Rus_ich [418]3 years ago
6 0
It is 8, because triangle=(bxh)/2
8x11=88
88/2=44
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It takes us of ribbon to make a hair bow. How much ribbon is needed to make 9 bows?
kherson [118]

Steps to Solve:

1. Simplify \frac{7}{2}: 3.5

2. Multiply 3.5 * 9: 31.5

Answer:

A = 31.5 yd

Notes:

N/A

3 0
3 years ago
I need it ASAP, Questions are attached as a photo
ELEN [110]

Answer:

8- 26 cm

7- 85 cm^2

1-23 cm

5 0
2 years ago
Helpppp asapppppp....
-BARSIC- [3]

Answer:

C.

Step-by-step explanation:

So, here's what you need to remember:

If we have a function <em>f(x)</em> and a factor <em>k</em>:

<em>k(f(x)) </em>will be a vertical stretch if k is greater than 1, and a vertical compression if k is greater than zero but less than 1.

<em>f(kx) </em>will be a horizontal compression if k is greater than 1, and a horizontal stretch if k is greater than zero but less than 1.

We are multiplying 0.5 to the function. In other words: 0.5f(x).

This is outside the function, so it's vertical.

0.5 is less than 1, so this would be a vertical compression

6 0
3 years ago
Teacl Smolts are young salmon at a stage when their skin becomes covered with silvery scales and they start to migrate from fres
erma4kov [3.2K]

Answer:

a) s = 8.81

b) Q1 = 43.4, Q2 = 49.4, Q3 = 57.35

c) See below

Step-by-step explanation:

(a) Find the standard deviation of the reflectance for these smolts. (Round your answer to two decimal places.)

In order to find the standard deviation, we need the mean first. The mean is defined as

\bar x=\displaystyle\frac{\displaystyle\sum_{i=1}^{n}x_i}{n}

where the x_i are the values of the data collected and n=50 the size of the sample.

So, the mean is

\bar x=50.882

Now, the standard deviation of the sample is defined as  

s=\sqrt{\displaystyle\frac{\displaystyle\sum_{i=1}^n(x_i-\bar x)^2}{n-1}}

and we have that our standard deviation is

s = 8.81

(b) Find the quartiles of the reflectance for these smolts

To find the quartiles, we must sort the data from lowest to largest:  

33.6,  37.7,  38.3,  38.7,  42,  42,  42.2,  42.4,  42.7,  42.8,  42.9,  43.1,  43.7,  43.8,  44.2,  44.6,  45.5,  45.7,  46.3,  46.6,  47.4,  47.6,  47.7,  47.9,  49.2,  49.6,  50.5,  50.9,  51.3,  53,  53.9,  54.8,  54.9,  55.5,  56,  56,  56.2,  57.1,  57.6,  58.3,  59,  59.5,  60.4,  63.2,  63.4,  63.5,  64.6,  68,  69.1,  69.2

The <em>first quartile</em> is the number between the 12th and the 13th data (so 25% of the data are below it and 75% above it)

So the 1st quartile is

Q_1=\displaystyle\frac{43.1+43.7}{2}=43.4

The <em>2nd quartile is the median</em>, the point between the 25th and 26th data, it splits the data in two halves.

Q_2=\displaystyle\frac{49.2+49.6}{2}=49.4

The 3rd quartile is the point between the 38th and 39th data (so 75% of the data are below it and 25% above it)

Q_3=\displaystyle\frac{57.1+57.6}{2}=57.35

(c) Do you prefer the standard deviation or the quartiles as a measure of spread for these data? Give reasons for your preference.

In this case, we prefer the quartiles as a measure of spread since the data are very scattered around the mean and there is no a central tendency.

3 0
3 years ago
Use a calculator to find a value of θ between 0° and 90° that satisfies the statement. Write your answer in degrees and minutes
Julli [10]

Answer:

\theta = 14.1\ degrees

846\ minutes

Step-by-step explanation:

Given

csc(\theta) = 4.1191

Required

Solve for \theta

csc(\theta) = 4.1191

csc(\theta) = \frac{1}{sin(\theta)}

So, we have:

\frac{1}{sin(\theta)} = 4.1191

Invert both sides

sin(\theta) = \frac{1}{4.1191}

sin(\theta) = 0.2428

Take sin^{-1} of both sides

sin^{-1} sin(\theta) = sin^{-1}0.2428

\theta = sin^{-1}0.2428

\theta = 14.0518577574

\theta = 14.1\ degrees --- approximated

Convert to minutes:

1\ degree = 60\ minutes

So:

14.1\ degrees = 14.1 * 60\ minutes

14.1\ degrees = 846\ minutes

4 0
3 years ago
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