Solve for X: 1/2(4+X)+2=16

1 answer:

5 0

1/2(4+X)+2=16
2+(0.5 x X) + 2 = 16
4 + (0.5 x X) = 16
0.5 x X = 12
X = 24

idk if u understand my working out - message me if u dont
hope it helped tho :)

You might be interested in

The length of a rectangle field is represented by the expression 14 X minus 3X squared +2 Y. The width of the field is represent

Assoli18 [71]

Answer:

$9x+4x^2-5y$

Step-by-step explanation:

Hi there!

Length of the field: $14x-3x^2+2y$ units

Width of the field: $5x-7x^2+7y$ units

To find how much greater the length of the field is than the width, subtract the width from the length:

$14x-3x^2+2y-(5x-7x^2+7y)$

Open up the parentheses

$= 14x-3x^2+2y-5x+7x^2-7y$

Combine like terms

$= 14x-5x-3x^2+7x^2+2y-7y\\= 9x+4x^2-5y$

Therefore, the length is $9x+4x^2-5y$ units greater than the width.

I hope this helps!

7 0

2 years ago

PLEASE can someone explain why The exact value of sec ( π/6) is 2 /√ 3 ??

Umnica [9.8K]

$\bf sec\left( \frac{\pi }{6} \right)\qquad recall\to sec(\theta)=\cfrac{1}{cos(\theta)}\qquad thus
\\\\
sec\left( \frac{\pi }{6}\right)\iff \cfrac{1}{cos\left( \frac{\pi }{6}\right)}
\\\\\\
\textit{check your Unit Circle for what the }cos\left( \frac{\pi }{6}\right)\ is
\\\\\\
\cfrac{1}{\frac{\sqrt{3}}{2}}\implies \cfrac{\frac{1}{1}}{\frac{\sqrt{3}}{2}}\implies 
\cfrac{1}{1}\cdot \cfrac{2}{\sqrt{3}}\implies \cfrac{2}{\sqrt{3}}$