Y^2+8y-9= (y+9) (?)
1 answer:
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4x - y + 3 =0 is the equation of the line
Step-by-step explanation:
Given:
The slope of the line = 5
The points through with the line passes = (0,3)
To Find:
The equation of the line =?
Solution:
The equation y = mx + b
where m is the slope and (0,b) is the y-intercept.
The slope is given which is m = 4 and a point (0,3)
Then you can use slope-point equation
where is the given point
y - (3) = 4(x - 0)
y - 3 = 4(x)
y = 4x - 22
y - 3 = 4x
4x - y + 3 = 0