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Valentin [98]
3 years ago
6

2 + − 1 ( − ) + 7 ( 2 − )

Mathematics
1 answer:
olasank [31]3 years ago
3 0

Answer:

Step-by-step explanation:

15

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HELP I'M SOOOOOO ANGRYYYYY PLEASE HELPPPP<br>determine the values of X for which g(x) is defined​
tiny-mole [99]

Answer: Any real number x as long as x \ne 0 and x \ne -\frac{2}{3}

In other words, anything but 0 or -2/3 is valid.

========================================================

Explanation:

Set the denominator equal to zero and solve for x

2(3x^2 + 2x) = 0

3x^2 + 2x = 0

x(3x + 2) = 0

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x = 0 or 3x = -2

x = 0 or x = -2/3

If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x)  will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.

Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.

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3 years ago
Convert 0∘F to ∘C. Round to one decimal place.
Gennadij [26K]

Answer:

(0°F − 32) × 5/9 = -17.78°C

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What is the probability of drawing two yellow marbles if the first one is NOT placed back into the bag before the second draw? T
Xelga [282]
Break it down into two parts. First, what is the probability of drawing a blue marble on the first draw?Since there are 5 blue marbles and 10 total, the probability is 5⁄10, or 1/2. Now since we no longer have that blue marble, there are 4 blue marbles and 9 total. The chances of drawing a blue marble are 4/9. Therefore, the chance that both marbles drawn are blue is the chance that the first one is blue times the chance that the second one is blue. 1/2 * 4/9 = 4/18 = 2/9 Remember, math is always trying to trick you. It wants you to try and do the whole big problem at once, which can be difficult. Break it down into smaller problems, then use your answers to small parts to find the answer to the big question.

Ishrat
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3 years ago
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