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2 years ago

PLEASE HELP WITH THESE TWO WUESTIONS ILL GIVE BRAINIEST AND GIVE YOU PTS

Mathematics

1 answer:

blondinia [14]2 years ago

4 0

The first one is the same amount of points

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Isosceles triangle $ABE$ of area 100 square inches is cut by $\overline{CD}$ into an isosceles trapezoid and a smaller isosceles

emmainna [20.7K]

Answer:

5 inches

Step-by-step explanation:

See attachment for explanation.

4 0

3 years ago

During a basketball practice, Mai attempted 49 free throws and was on 25% of them. How many successful free throws did she make?

Brrunno [24]

Mai made 12 successful free throws.

Step-by-step explanation:

Given,

Free throws made by Mai = 49 free throw

Successful throws = 25%

Number of successful throws = 25% of free throws

Number of successful throws = $\frac{25}{100}*49$

Number of successful throws = $\frac{1225}{100} = 12.25$

Rounding off to nearest whole number;

Number of successful throws = 12

Mai made 12 successful free throws.

Keywords: percentage, division

Learn more about division at:

#LearnwithBrainly

6 0

3 years ago

Plss help!<br>Question: Find a,b and c

Roman55 [17]

Answer:

See below, please

Step-by-step explanation:

The right：

${(y + c)}^{2} - b \times (x + a) \\ = ( {y}^{2} + 2yc + {c}^{2} ) - bx - ba =$

$= {y}^{2} - bx + 2cy + {c}^{2} - ab$

The left:

$= {y}^{2} - 7x - 18y + 109$

So, after comparing the right side and the left side of this equation, we know

$b = 7$

$2c = - 18 \\ so \\ c = - 9$

${c}^{2} - ab = 109$

So,

$a = \frac{ {c}^{2} - 109}{b} = \frac{ { (- 9)}^{2} - 109}{7} = \frac{ - 28}{7} = - 4$

6 0

2 years ago

How do I solve this

Kitty [74]

Hello,

$x^2-2x-27=-5x+1\\

x^2-2x+5x-27-1=0\\

x^2+3x-28=0\\

x^2+7x-4x-28=0\\

x(x+7)-4(x+7)=0\\

(x+7)(x-4)=0\\

x=-7\ or\ x=4\\
$

8 0

3 years ago

Read 2 more answers

FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM

algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

$S_{n}$ = $\frac{n}{2}$ [ 2a₁ + (n - 1)d ] , thus

$S_{20}$ = $\frac{20}{2}$ [ (2 × - 1) + (19 × 4) ]

= 10(- 2 + 76) = 10 × 74 = 740

8 0

3 years ago