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2 years ago

Help!!! Fast!!!!!!!!!!

Mathematics

2 answers:

Furkat [3]2 years ago

8 0

√9=3

√64=8

√=10

3 √729=9
3 √343=7

3√216=6
Hope this helped. If it did I would appreciate it if you could give me brainliest

prohojiy [21]2 years ago

6 0

Daaaaaaaaaaaaamn that’s a lot of math

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Review the proof of de Moivre’s theorem.

RideAnS [48]

Answer:

Step-by-step explanation:

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3 years ago

Determine if events A and B are mutually exclusive.

gladu [14]

Answer:

A) Not mutually exclusive

Step-by-step explanation:

Given

$P(A) = \frac{1}{4}$

$P(B) = \frac{3}{5}$

$P(A\ or\ B) = \frac{7}{10}$

Required

Determine if they are mutually exclusive or not

Mutually exclusive are defined by:

$P(A\ or\ B) = P(A) + P(B)$

So, we have:

$P(A\ or\ B) = \frac{1}{4} + \frac{3}{5}$

Take LCM

$P(A\ or\ B) = \frac{5+12}{20}$

$P(A\ or\ B) = \frac{17}{20}$

By comparing:

$P(A\ or\ B) = \frac{17}{20}$ ---- Calculated

$P(A\ or\ B) = \frac{7}{10}$ ---- Given

We can conclude that A and B are not mutually exclusive because:

$\frac{17}{20} \ne \frac{7}{10}$

6 0

3 years ago

A geometric sequence is shown below.

mestny [16]

Answer:

An explicit representation for the nth term of the sequence:

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

It means, option (B) should be true.

Step-by-step explanation:

Given the geometric sequence

$-\frac{1}{2},\:-2,\:-8,\:-32,...$

A geometric sequence has a constant ratio, denoted by 'r', and is defined by

$f_n=f_1\cdot r^{n-1}$

Determining the common ratios of all the adjacent terms

$\frac{-2}{-\frac{1}{2}}=4,\:\quad \frac{-8}{-2}=4,\:\quad \frac{-32}{-8}=4$

As the ratio is the same, so

r = 4

Given that f₁ = -1/2

substituting r = 4, and f₁ = -1/2 in the nth term

$f_n=f_1\cdot r^{n-1}$

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

Thus, an explicit representation for the nth term of the sequence:

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

It means, option (B) should be true.

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2 years ago

83/6 as a mixed number

jonny [76]

$\frac{83}{6}=13\frac{5}{6}$

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2 years ago

Which expression is equivalent to 3\tfrac{1}{3}-8\tfrac{2}{3}3

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Answer:

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