The energy is compared based on the information given below.
<h3>How to illustrate the energy?</h3>
Energy released by burning 1 kilogram of element A = EA = 5.1 * (10)8
Energy released by fission of hydrogen in 1 kilogram of element B = EB = 1.3 * (10)10
Therefore,
Ratio = EB / EA = 1.3 * (10)10 / 5.1 * (10)8 = 25
Thus, the fission of 1 kg of element B releases 25 times as much energy as burning 1 kilogram of element A.
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<u>The other part of the question:</u>
Energy released by burning 1 kilogram of element A = 5.1 times 10 Superscript 8
Energy released by the fission of hydrogen in 1 kilogram of element B = 1.3 times 10 Superscript 10
Answer:
5/4
Step-by-step explanation:
1.2.3.4.5.6.7.8.9.10.11.12.13.14.15.16.17.18.19.2p
Answer:
140
Step-by-step explanation:
multiply 5x4x7 and u will get ur answer
For f(x) = cos(x) we have:
- midline = 0
- amplitude = 1
- period = 2π
- graph = bottom graph on the second image.
<h3>
What are the midline, amplitude, period, and graph of the function f(x)=cos(x)?</h3>
For a general cosine function, we have:
f(x) = A*cos(kx + p) + M
Where:
- A is the amplitude.
- k is the frequency.
- p is the phase.
- M is the midline.
For the function:
f(x) = cos(x).
We can see that:
A = 1, M = 0, k = 1, p = 0.
So, the amplitude is equal to 1, and the midline is equal to zero.
Now we also need to get the period. By definition of the trigonometric functions sin(x) and cos(x), we know that the period of the two is equal to 2π.
Finally, we need to identify the graph of cos(x).
Notice that:
f(0) = cos(0) = 1.
So the graph of f(x) = cos(x) is the graph with an y-intercept equal to 1. Which is the bottom graph on the second image.
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Answer:
depending on what is happening then ye
Step-by-step explanation:
