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anyanavicka [17]

3 years ago

11

Please help due in 5 minutes

1 answer:

alukav5142 [94]3 years ago

3 0

Add y subtract 6. Ur left with y=x-6
Add the equations and ur left with 2x-10

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Please need help thank you

valentinak56 [21]

Might be 1? Because it is 100 each

5 0

3 years ago

Which triangle is a rotation of triangle 3?<br><br><br><br> Δ1<br> Δ2<br> Δ3<br> Δ4

nikdorinn [45]

Answer:

1

Step-by-step explanation:

6 0

2 years ago

For the following system, if you isolated x in the first equation to use the substitution method, what expression would you subs

Musya8 [376]

Answer:

x = 2y + 6

Step-by-step explanation:

5 0

2 years ago

Are AB and CD parallel, perpendicular, or neither?*<br> 1. A(-4, 8), B(4, 10), C(1, 1), D(-2, 13)

ohaa [14]

Answer:

Perpendicular

<em />

Step-by-step explanation:

Given

$A = (-4, 8)$

$B = (4, 10)$

$C = (1, 1)$

$D = (-2, 13)$

Required

Is AB and CD parallel?

First, we need to calculate the slope (m) of AB and CD

$m = \frac{y_2 - y_1}{x_2 - x_1}$

For AB:

$A (x_1,y_1)= (-4, 8)$

$B(x_2,y_2) = (4, 10)$

So:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{10 - 8}{4 - (-4)}$

$m = \frac{10 - 8}{4 +4}$

$m = \frac{2}{8}$

$m = \frac{1}{4}$

For CD:

$C(x_1,y_1) = (1, 1)$

$D(x_2,y_2) = (-2, 13)$

So:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{13 - 1}{-2 - 1}$

$m = \frac{12}{-3}$

$m = -4$

For Lines to be parallel, the slope must be equal:

i.e. $m_1 = m_2$

This condition is not true because:

$\frac{1}{4} \neq -4$

For Lines to be perpendicular, the slope must be:

$m_1 = -\frac{1}{m_2}$

This implies:

$\frac{1}{4} = -\frac{1}{-4}$

$\frac{1}{4} = \frac{-1}{-4}$

$\frac{1}{4} = \frac{1}{4}$

<em>Hence, the lines are perpendicular</em>

6 0

3 years ago

A student has scores of 64, 62, and 72 on his first three tests. He needs an average of at least 70

kotegsom [21]

Answer:

73 or more

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers