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3 years ago

What is the value of x?

Mathematics

1 answer:

algol133 years ago

6 0

Answer: 10^2 = x^2 plus 6^2

100= x^2 + 36

64=x^2

Step-by-step explanation:

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A bag contains 15 cups of sugar if 3/4 of a cup is needed for each batch of cookies what's the greatest number of batches of coo

tensa zangetsu [6.8K]

Answer:

20 batches

Step-by-step explanation:

Cups of sugar in a bag = 15

Cups of sugar per batch of cookie = 3/4 cup

Cups of sugar per batch of cookie : batch of cookies = 3/4 : 1

what's the greatest number of batches of cookies that can be made with the bag of sugar

Let

x = batches of cookies made with a bag of sugar

Cups of sugar per batch of cookie : batch of cookies = 15 : x

Equate the ratios

3/4 : 1 = 15 : x

3/4 ÷ 1 = 15/x

3/4 × 1/1 = 15/x

3/4 = 15/x

Cross product

3 * x = 4 * 15

3x = 60

x = 60/3

x = 20

x = batches of cookies made with a bag of sugar = 20 batches

8 0

3 years ago

If 2/3 equals = X/12 what is the value of x

Blizzard [7]

Answer:

the answer is

x=8

Step-by-step explanation:

3x = 24

divide

6 0

3 years ago

Read 2 more answers

Plzz I beg someone to finish ALL of this :(. I’ve stayed up all night to do this but I couldn’t figure all of them out. Pls pls

Anika [276]

13. 9:55
14. 8:10
15. 1 hour 45 minutes
16. 3:05

7 0

3 years ago

Simplify (2x + 1) (3.1 – 6)using the Distributive Property or the Area Method.

Tju [1.3M]

Answer: -5.8x-2.9

Step-by-step explanation:

Hi, to answer this we will use the distributive property:

The distributive property allows to multiply a sum by multiplying each addend separately and then add the products.

(2x + 1) (3.1 – 6)

(2x [3.1]) +(2x[-6])+ (1 [3.1])+ (1 [-6])

6.2x-12x+3.1-6

-5.8x-2.9

Feel free to ask for more if needed or if you did not understand something.

4 0

4 years ago

Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, find the body

nika2105 [10]

Answer:

The position at time t is $s(t) = 8t^2 - 14t -8$

Step-by-step explanation:

From the question we are told that

The acceleration is $a = 16$

The velocity at t = 0 is $v(0) = -14$

The position at time t = 0 is $s(0) = -8$

Generally acceleration is mathematically represented as

$a(t) = \frac{d v}{dt }$

=> $\frac{dv}{dt} = 16$

=> $dv = 16 dt$

integrating both sides we have

$\int\limits dv = \int\limits16 dt$

=> $v(t) = 16 t + c$

Now at t = 0

$v(0) = 16 * 0 +c = -14$

=> $c = -14$

$v(t) = 16 t -14$

Generally the position of the body is mathematically represented as

$s(t) = \int\limits v(t)dt$

$s(t) = \int\limits 16t - 14 dt$

$s(t) = 16 \frac{t^2}{2} - 14t + C$

Now at t = 0

$s(0) = 16 \frac{0^2}{2} - 14(0) + C = -8$

=> $C = -8$

$s(t) = 8t^2 - 14t -8$

5 0

3 years ago