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Elan Coil [88]
3 years ago
6

Mr. Williams is planning a seventh grade field trip to a math museum school policy requires a minimum of two adults as chaperone

s for every nine students on the trip and allows the food budget to six dollar per person educational group pricing at the museum is $4.50 per student and $7.25 per adult there’s also a bus parking fee that is 4% of the total ticket price they’re 171 students in seventh grade how much money does Mr. Williams need to budget for the museum tickets and parking
Mathematics
1 answer:
never [62]3 years ago
6 0
To figure out how much to budget, Mr. Williams will need to determine how many people (students and adults) are going on the trip.

If there are 171 7th graders, there will need to be 38 adults (2 adults per 9 students is 38 adults for 171 students.

This is a total of 209 people(171 students and 38 adults).

$6 per person x 209 people = $1254 for food

$4.50 x 171 + $7.25 x 38 = $1045 Cost for tickets to the museum

0.04(4%) x 1045 = $41.80 for parking

For the museum tickets and parking Mr. Williams will need to budget $1045 + $41.80 = $1086.80 for parking and tickets.

If you are including the food cost you would need to add $1254 to this.
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7. Are the ordered pairs below an arithmetic sequence or geometric
DochEvi [55]

Answer:

8. Arithmetic Progression

9. f(9) = 300

Step-by-step explanation:

Given

\{(1,55)\ (2, 45)\ (3, 35)\ (4, 25)\}

Solving (8): Arithmetic or Geometric

We start by checking if it is arithmetic by checking for common difference (d).

d = y_2 - y_1 = y_3 - y_2 = y_4 - y_3

This gives:

d = 45 - 55 = 35 - 45 = 25 - 35

d = -10 = -10 = -10

d=-10

<em>Because the common difference is equal, then it is an arithmetic progression</em>

<em></em>

Solving (8):

f(n) = f(1) + f(n-1)

To find f(9), we substitute 9 for n

f(9) = f(1) + f(9-1)

f(9) = f(1) + f(8)

We need to solve for f(8); substitute 8 for n

f(8) = f(1) + f(8 - 1)

f(8) = f(1) + f(7)

We need to solve for f(7); substitute 7 for n

f(7) = f(1) + f(7 - 1)

f(7) = f(1) + f(6)

We need to solve for f(6); substitute 6 for n

f(6) = f(1) + f(6 - 1)

f(6) = f(1) + f(5)

We need to solve for f(5); substitute 6 for n

f(5) = f(1) + f(5 - 1)

f(5) = f(1) + f(4)

From the function, f(4) = 25 and f(1) = 55.

So:

f(5)=55 + 25

f(5)=80

f(6) = f(1) + f(5)

f(6) = 55 + 80

f(6) = 135

f(7) = f(1) + f(6)

f(7) = 55 + 135

f(7) = 190

f(8) = f(1) + f(7)

f(8) = 55 + 190

f(8) = 245

f(9) = f(1) + f(8)

f(9) = 55 + 245

f(9) = 300

8 0
3 years ago
PLEASE ANSWER ASAPP I HAVE A PICTURE ATTACHED
Alik [6]
Its c I've done this before
3 0
2 years ago
Read 2 more answers
What statements are true about the ordered pair (7,19) and the system of equations?
Tju [1.3M]

Answer:C


Step-by-step explanation:


3 0
3 years ago
Jack has a rectangular patio with a length that is one foot less than twice its width. His neighbor Ron's patio has the same wid
swat32

Answer:

difference in area = 16 ft²

if you use 8 the difference in length between Jack patio and his neighbor patio will be will be 15 - 13 = 2 ft

if you use 13 the difference i length will be 25 - 18 = 7 ft

Step-by-step explanation:

Jacks rectangular patio

width = a

length = 2a - 1

area = lw

where

l = length

w = width

area = 120 ft²

a(2a - 1)

2a² - a - 120 = 0

(a - 8) (2a + 15)

a = 8 or -15/2

Ron's rectangular patio

width = a

length = a + 5

area = lw

area = 104 ft²

a (a + 5) = 104

a² + 5a -104 = 0

(a + 8)  (a - 13)

a = -8 or 13

How many square feet longer is jack patio longer than Ron's patio is the difference in their area. Therefore,

120 - 104 = 16 ft²

The value 8 or 13 can be used for a since the width a have to be the same.

if you use 8 the difference in length between Jack patio and his neighbor patio will be will be 15 - 13 = 2 ft

if you use 13 the difference i length will be 25 - 18 = 7 ft

6 0
3 years ago
Dana leaves Las Vegas for LA at 2 p.m. driving at 55 mph. At 4 p.m. Lance leaves LA for Las Vegas driving at 45 mph along the sa
NNADVOKAT [17]

Answer: They meet after 1 hour 42 minutes.

Step-by-step explanation:

Since we have given that

Dana leaves Las Vegas for LA at 2 p.m. driving at 55 mph.

Let the time taken by Dana be 't'.

Distance traveled by Dana would be 55t.

At 4 p.m. Lance leaves LA for Las Vegas driving at 45 mph along the same route.

It means after 2 hours Lance leave for LA.

So, time taken by Lance be 't-2'.

Distance traveled by Lance would be 45(t-2)

Total distance  = 260 miles

According to question, it becomes,

55t+45(t-2)=260\\\\55t+45t-90=260\\\\100t=260-90\\\\100t=170\\\\t=1.7\ hours=1\dfrac{7}{10}=1\ hour\ and\ \dfrac{7\times 60}{10}\ minutes=1\ hour\ 42\ minutes

Hence, they meet after 1 hour 42 minutes.

4 0
3 years ago
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