1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
PtichkaEL [24]
2 years ago
6

If f(x)=6x^2 and g(x)=14x + 4 solve (g o f)(2) Choices: 340 465 336 284

Mathematics
2 answers:
Law Incorporation [45]2 years ago
8 0

The answer is 340

Explanation:

(g o f)(2) = g(f(2))

f(2) = 6(2)² = 24

g(f(2)) = g(24) = 14(24) + 4 = 336 + 4 = 340

m_a_m_a [10]2 years ago
6 0
The answer to the question is 340
You might be interested in
What are the missing numbers?
n200080 [17]
2^2. 2 and 2. Because 2 and 2
8 0
3 years ago
What is the credit-to-debit ratio on the handy hardware credit card?
olga nikolaevna [1]

The debt-to-credit ratio of a credit account is the ratio of the balance to the credit limit:

... balance/credit limit = 245.78/3500 = 0.07022... ≈ 7.02%

The appropriate choice is ...

... A.) 7.02%

7 0
3 years ago
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
Which equation has the same solutions as the equation given below?
Lapatulllka [165]

Answer:

B

Step-by-step explanation:

Also solved eveything

(x+9)^2=49

x^2+18x+81=49

x^2+18x+32=0

a=1, b=18 and c=32

x= (-18 +/- Sqrt (18^2-4×32))/2

x= (-18 +/- Sqrt (324-128))/2

x= (-18 +/- Sqrt (196))/2

x= (-18 +/- 14)/2

x= (-18 +14)/2 = -4/2 =-2

OR

x= (-18 -14)/2 = -32/2 =-16

3 0
3 years ago
Read 2 more answers
Question 15 (5 points)
serg [7]

Answer:

You need to attach the pictures and ask again.

Step-by-step explanation:

I cannot see any attachments.

8 0
2 years ago
Other questions:
  • . Complete the missing steps in the paragraph proof of Theorem 3-8.
    14·1 answer
  • Simplify the expression -4(x - 5)
    11·1 answer
  • Rewrite the parametric equations by eliminating the parameter:
    7·2 answers
  • Estimate 15 square root to the nearest ten
    6·1 answer
  • Chuck says that he can draw a cylinder on his polyhedron poster because it has a pair of base that are congruent. is chuck corre
    7·1 answer
  • Which expression is equivalent to x^2-10x+24
    10·1 answer
  • Add the polynomials. <br><br> 1. (-4x^2+2x+6)+(5x^2-x+10)<br><br> 2. (5x^2-9x+2)+(-3x^2+2x+4)
    12·1 answer
  • What value of n makes the equation true? Show your work.
    8·1 answer
  • Write the equation of the line that passes through the points (-9,3) and (8,3). Put
    6·2 answers
  • Bob claimed down a ladder from his roof, while Roy climbed up another ladder next to him. Each ladder had 26 rungs. Bob went dow
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!