Ask question

Ask question

All categories

3 years ago

6

If f(x)=6x^2 and g(x)=14x + 4 solve (g o f)(2) Choices: 340 465 336 284

2 answers:

Law Incorporation [45]3 years ago

8 0

The answer is 340

Explanation:

(g o f)(2) = g(f(2))

f(2) = 6(2)² = 24

g(f(2)) = g(24) = 14(24) + 4 = 336 + 4 = 340

m_a_m_a [10]3 years ago

6 0

The answer to the question is 340

You might be interested in

A^2 + b^2 + c^2 = 2(a − b − c) − 3. (1) Calculate the value of 2a − 3b + 4c.

Verdich [7]

Answer:

$2a - 3b + 4c = 1$

Step-by-step explanation:

Given

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Required

Determine $2a - 3b + 4c$

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Open bracket

$a^2 + b^2 + c^2 = 2a - 2b - 2c - 3$

Equate the equation to 0

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 3 = 0$

Express 3 as 1 + 1 + 1

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 1 + 1 + 1 = 0$

Collect like terms

$a^2 - 2a + 1 + b^2 + 2b + 1 + c^2 + 2c + 1 = 0$

Group each terms

$(a^2 - 2a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

Factorize (starting with the first bracket)

$(a^2 - a -a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$(a(a - 1) -1(a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1) (a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + b+b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b(b + 1)+1(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + c+c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c(c + 1)+1(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)^2) = 0$

Express 0 as 0 + 0 + 0

$(a - 1)^2 + (b + 1)^2 + (c + 1)^2 = 0 + 0+ 0$

By comparison

$(a - 1)^2 = 0$

$(b + 1)^2 = 0$

$(c + 1)^2 = 0$

Solving for $(a - 1)^2 = 0$

Take square root of both sides

$a - 1 = 0$

Add 1 to both sides

$a - 1 + 1 = 0 + 1$

$a = 1$

Solving for $(b + 1)^2 = 0$

Take square root of both sides

$b + 1 = 0$

Subtract 1 from both sides

$b + 1 - 1 = 0 - 1$

$b = -1$

Solving for $(c + 1)^2 = 0$

Take square root of both sides

$c + 1 = 0$

Subtract 1 from both sides

$c + 1 - 1 = 0 - 1$

$c = -1$

Substitute the values of a, b and c in $2a - 3b + 4c$

$2a - 3b + 4c = 2(1) - 3(-1) + 4(-1)$

$2a - 3b + 4c = 2 +3 -4$

$2a - 3b + 4c = 1$

7 0

3 years ago

What is the slope of the line through(-5,-10) and (-1,5)

Akimi4 [234]

<span> Put the values of above points in the equation of straight </span>line<span> point-</span>slope<span> form m=(y2-y1)/(x2-x1) m=(-</span>5-(-10))/(-1-5) m=(-5+10)/(-6) m=5/-6 m=-5<span>/6. </span>Slope of the line<span> = m = -</span>5<span>/6 so the answer is 5/6</span>

7 0

3 years ago

Read 2 more answers

The diagram shows one way to develop the formula for the area of a circle. Pieces of a circle with radius r are rearranged to cr

IRINA_888 [86]

Answer:

A = 1/2(2πr)(r)

Explanation:

The circumference of the circle, 2πr, is the measure completely around the circle. When the pieces of the circle are rearranged, half of this circumference will be on the top of the parallelogram and half will be on the bottom. This means the base will be 1/2(2πr).

The approximate height of the parallelogram is the radius of the circle; this makes the area

A = 1/2(2πr)(r)

7 0

3 years ago

Read 2 more answers

On a horizontal number line, numbers are what

Vikentia [17]

Answer:

to the right of zero if postive if negative left

6 0

2 years ago

Read 2 more answers

(6x -8)(2x -3)<br><br> B) 12x2 + 24 <br> U) 70x<br> L) 8x2 - 21x + 11 <br> E) 12x2 -34x + 24

deff fn [24]

Answer is E!
12x^2-34x+24

5 0

3 years ago

Read 2 more answers