Step-by-step explanation:
First divide 1100 by 2
550
Now that would be the amount the both of them would have to pay if they were splitting it equally. Since there not add 250 to 550.
250+550=800
Finally subtract 250 from 550
550-250=300
Jake has to pay $550
Danny has to pay $300
Answer:
24cb 18 hb
Step-by-step explanation:
Let's call C the number of cheese burger sold and H the number of hamburgers.
As the cheeseburger sold are 3/4 of hamburgers, we can represent with the following equation:
C= (3/4)H (equation 1)
The total of burgers sold are the total of cheeseburger plus the total of hamburgers, and the sum 42. The equation representing it is:
C + H = 42
Replacing C by its value of eq. 1:
(3/4)H + H = 42
(3/4)H + (4/4)H = 42
(7/4) H = 42
Dividing both sides by (7/4)
H = 42/(7/4)
H= 42*(4/7)
H= (42/7)*4
H= 6*4
H=24
Then, C is:
C=(3/4)H
C=(3/4)*24
C= 3*24/4
C=72/4
C=18
We can verify it summing C+H
C+H=24+18=42 verified!
Https://photomath.net/s/o2P0wN
Answer:
all you have to do is graph them but put them in y=mx+b form first, the coordinates is the solution
Check the picture below.
so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?
now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.
![\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%20in%20feet%7D%20%5C%5C%5C%5C%20h%28x%29%20%3D%20-16x%5E2%2Bv_ox%2Bh_o%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Ctextit%7Binitial%20velocity%7D%260%5C%5C%20%5Cqquad%20%5Ctextit%7Bof%20the%20object%7D%5C%5C%20h_o%3D%5Ctextit%7Binitial%20height%7D%26%5C%5C%20%5Cqquad%20%5Ctextit%7Bof%20the%20object%7D%5C%5C%20h%3D%5Ctextit%7Bobject%27s%20height%7D%260%5C%5C%20%5Cqquad%20%5Ctextit%7Bat%20%22t%22%20seconds%7D%5C%5C%20x%3D%5Ctextit%7Bseconds%7D%261%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%200%3D-16%281%29%5E2%2B0x%2Bh_o%5Cimplies%200%3D-16%2Bh_o%5Cimplies%2016%3Dh_o%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20h%28x%29%20%3D%20-16x%5E2%2B16~%5Chfill)
quick info:
in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².
