Answer:
Hi! The answer to your question is C. 52
Step-by-step explanation:
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Hope this helps!
- Brooklynn Deka
The only things you can factor out of here is a 3 so you are left with:
3(y-6)
Hope that helps.
Answer:
No, it cannot have a unique solution. Because there are more variables than equations, there must be at least one free variable. If the linear system is consistent and there is at least one free variable, the solution set contains infinitely many solutions. If the linear system is inconsistent, there is no solution.
Step-by-step explanation:
the questionnaire options are incomplete, however the given option is correct
We mark this option as correct because in a linear system of equations there can be more than one solution, since the components of the equations, that is, the variables are multiple, leaving free variables which generates more alternative solutions, however when there is no consistency there will be no solution
The first step for absolute value equations is to isolate the expression contained within the absolute value bars:
3|2x+4|-1 = 11
3|2x+4| = 12
|2x+4| = 4
so |2x+4| is 4 units away from 0 on a number line, but we don't know in which direction -- negative or positive? you'll have two answers.
2x+4 = 4
AND
2x+4 = -4
solve both of those two step equations and you'll get
x = 0
AND
x = -4
so 0 and -4 are your solutions.
(10 1/2)/(3/8)
= (21/2)/(3/8) Convert to improper
= (21/2)*(8/3) Multiply by reciprocal of second
=(7/1)*(4/1) Cross reduce
=28 Multiply
