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algol13
3 years ago
5

Sixty six times times the swuare of a number equals sixty nine i(n number form)

Mathematics
1 answer:
Nookie1986 [14]3 years ago
6 0

Answer: 3

Step-by-step explanation:

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Use a model to solve 1/8*9
sergiy2304 [10]

Answer:

9/8

Step-by-step explanation:

1/8*9=9/8

5 0
3 years ago
Farmer jones, and his wife, dr. jones, decide to build a fence in their field, to keep the sheep safe. since dr. jones is a math
sweet [91]

Consider the attached figure (note that the axis are not in a 1:1 scale).

We want the (finite) area between the two parabolas, where y = 6x^2 is the green one, and y = x^2+10 is the red one.

We need the following result: given a function f, the integral

\displaystyle \int_a^b f(x)\; dx

returns the area between the function and the x axis.

So, if we subtract the area below the green function between points A and B from the area below the red function between points A and B, we have exactly the area between the two. So, we need the x coordinates of points A and B.

Since they are the points of interception between the two parabolas, we can compute them by solving the equation

6x^2 = x^2+10 \implies 5x^2=10\implies x^2=2 \implies x=\pm\sqrt{2}

So, we need

\displaystyle \int_{-\sqrt{2}}^{\sqrt{2}} (x^2+10)-6x^2 = \int_{-\sqrt{2}}^{\sqrt{2}} -5x^2+10

The primitive of this function is

F(x) = -\cfrac{5x^3}{3} + 10x + C

And we need to compute it at the two endpoints: the area is given by

A = F(\sqrt{2}) - F(-\sqrt{2}) = \cfrac{20\sqrt{2}}{3} - (- \cfrac{20\sqrt{2}}{3}) = \cfrac{40\sqrt{2}}{3}

8 0
4 years ago
Translate the equation, using "n" as your variable. "three times the difference of a number and 7 is 18" *
Dafna1 [17]

Answer:

3(n - 7) = 18

Step-by-step explanation:

three times the difference of a number and 7 is 18

three times the difference of a number and 7 = 18

three times (n - 7) = 18

3(n - 7) = 18

7 0
3 years ago
In a small Library there are five non-fiction books for every nine fiction book there are 130 Non-fiction books how many fiction
vova2212 [387]

Answer:

For 130 non-fiction books, the number of fiction books can be from 270 to 278.

Step-by-step explanation:

Given that, there are 5 non-fiction books for every 9 fiction books.

Observe that, if the number of fiction books is less than 9, than there will be no no-fiction books.

So, there are 5 non-fiction books for every 9 to (9+8) fiction books

So, by elementary method, there will be 5n non-fiction books for every 9n+8 fiction books, where n is a natural number.

Or, if the number of non-fiction books is 5n, then the number of fiction books will be ranging from 9n to (9n+8).

For, 150 non-fiction books, 5n=150 or n=150/5=30.

Hence, the number of fiction books can be from 9n to (9n+8).

=9x30 to (9x30+8)

=270 to 278.

Hence, for 130 non-fiction books, the number of fiction books can be from 270 to 278.

6 0
4 years ago
Which of the pictures below shows the graph of the inequality y≥x-2?
Ostrovityanka [42]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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