We know that
a(n)=4n+1
To find the sum of the first n<span> terms of an arithmetic series
use the formula
</span><span><span>Sn</span>=<span>n(<span>a1</span> + <span>an</span>)/2
</span></span>a1--------------> is the first term
an--------------> is the last term
n--------------- > <span>is the number of terms
</span>we have that
a1------------> 4*(1)+1=5
a30----------> 4*(30)+1=121
n------------- > 30
S30=30*(5 + 121)/2=1890
the answer is 1890
Answer:
sup
Step-by-step explanation:
The binomial expansion:

a = 2y, b = 4 x^3, n = 4
( x )^3k = x^ 9
k = 3


Answer: the coefficient is
512.
Answer:
1/2
Step-by-step explanation:
2/3-1/6
=4/6-1/6
=3/6
=1/2
Answer:
c
Step-by-step explanation: