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3 years ago

What is the height of a solid with a volume of 120m and base area of 30m

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

4 0

Answer:

4m.

Step-by-step explanation:

Divide the total volume by the base area to find the height. This is because the volume of a solid is equal to the base area multiplied by the height.

120/30=4

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stiv31 [10]

A and b proves that they are parallel

4 0

3 years ago

the amount of gasoline used by a car varies jointly as the distance travelled and the square root of the speed.Suppose a car use

klemol [59]

Answer:

200 litres

Step-by-step explanation:

let g be gasoline used, d the distance travelled and s the speed, then the equation relating the quantities is

g = kd $\sqrt{s}$ ← k is the constant of variation

To find k use g = 25, d = 100 and s = 100, then

25 = k × 100 × $\sqrt{100}$ = k × 100 × 10 = 1000k ( divide both sides by 1000 )

0.025 = k

g = 0.025d $\sqrt{s}$ ← equation of variation

When d = 1000 and s = 64, then

g = 0.025 × 1000 × $\sqrt{64}$ = 0.025 × 1000 × 8 = 200

4 0

3 years ago

Find the domain of the graphed function.

Tpy6a [65]

Dddddddddddddddddddddd

8 0

3 years ago

. Consumer Awareness In 1986, the average cost of a new midsize four-door sedan was $9000. In 1991, the average cost was $12,000

eduard

Answer-

$\boxed{\boxed{y=9000(1.0592)^x}}$

And cost of a car in the year 2000 will be $20134.18

Solution-

Let's assume,

x = number of years after 1986

y = average cost of sedan in dollar

The exponential model that will model the scenario will be in the form of,

$y=ab^x$

where a and b are constants

As given that, in 1986 average cost of sedan was $9000 and in 1991 average cost of sedan was $12000

So, the points (0, 9000) and (5, 12000) will satisfy or lie on the exponential curve.

Putting (0, 9000) in the equation,

$\Rightarrow 9000=ab^0$

$\Rightarrow a\times 1=9000$

$\Rightarrow a=9000$

Now, the equation becomes $y=9000b^x$

Putting (5, 12000) in this equation,

$\Rightarrow 12000=9000b^5$

$\Rightarrow b^5=\dfrac{12000}{9000}$

$\Rightarrow b=\sqrt[5]{\dfrac{4}{3}}$

$\Rightarrow b=1.0592$

Putting the values,

$y=9000(1.0592)^x$

As we have to calculate the cost of sedan in 2000, so putting x=14(as 2000-1986=14),

$y=9000(1.0592)^{14}=20134.18$

Therefore, cost of a car in the year 2000 will be $20134.18

8 0

3 years ago

Consider w=sqrrt2/2(cos(225°) + isin(225°)) and z = 1(cos(60°) + isin(60°)). What is w+ z expressed in rectangular form?

SVETLANKA909090 [29]

Answer:

Option (3)

Step-by-step explanation:

w = $\frac{\sqrt{2}}{2}[\text{cos}(225) + i\text{sin}(225)]$

Since, cos(225) = cos(180 + 45)

= -cos(45) [Since, cos(180 + θ) = -cosθ]

= - $\frac{\sqrt{2}}{2}$

sin(225) = sin(180 + 45)

= -sin(45)

= - $\frac{\sqrt{2}}{2}$

Therefore, w = $\frac{\sqrt{2}}{2}[-\frac{\sqrt{2}}{2}+i(-\frac{\sqrt{2}}{2})]$

= $-\frac{2}{4}(1+i)$

= $-\frac{1}{2}(1+i)$

z = 1[cos(60) + i(sin(60)]

= $[\frac{1}{2}+i(\frac{\sqrt{3}}{2})$

= $\frac{1}{2}(1+i\sqrt{3})$

Now (w + z) = $-\frac{1}{2}(1+i)+\frac{1}{2}(1+i\sqrt{3})$

= $-\frac{1}{2}-\frac{i}{2}+\frac{1}{2}+i\frac{\sqrt{3}}{2}$

= $\frac{(i\sqrt{3}-i)}{2}$

= $\frac{(\sqrt{3}-1)i}{2}$

Therefore, Option (3) will be the correct option.

3 0

3 years ago

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