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3 years ago

Xavier is buying bottled water for his basketball team. If he has $20 to spend on water, and each bottle of water

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

1.5 * 13 = 19.5 dollars

0.50 = 20 - 1.5x where 0.50 is the amount of money he has left and x is the number of bottles of water he buys

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Find the m∠1, if p|| q, and m∠4 = 125 degrees. m∠1 =

polet [3.4K]

Step-by-step explanation:

m<5=180-m<4 (linear pair)

m<5=180-125 = 55°

m<5=m<1 ( alternate angle)

therefore, m<1 = 55°.

hope this helps you.

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2 years ago

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An orange has about 1/4 cups of juice.Hiw many Oranges are needed to make 2 1/2 cups of juice?

marysya [2.9K]

Answer:

10/4 cups of juice

Step-by-step explanation:

4/4 = 1

so 4/4 + 4/4 = 2

and 1/2 = 2/4

then add

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3 years ago

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I'LL G IVE U 42 POINTS JUST ANSWER TH IS QUICK PLEASE!!

ZanzabumX [31]

Answer:

The surrender of Detroit

Step-by-step explanation:

The other two were american victories, the surrender of Detroit was a Indian/British victory and an early one in the war

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2 years ago

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What is the constant of variation for the quadratic variation? x=2,3,4,5,6 y= 32,72,128,200,288

Bad White [126]

Hello,
y=a*x² ==>
32=a*2²==>a=32/4=8
72=a*3²==>a=72/9=8
128=a*4²==>a=128/16=8
200=a*5²==>a=200/25=8
288=a*6²==>a=288/36=8

Answer A: 8

7 0

2 years ago

Simplify each expression. Assume that all variables are positive.

kozerog [31]

Q1. The answer is $\frac{8x^{3}y^{6} }{27}$

$( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} } \\ \\ 
 \frac{ x^{a} }{ x^{b} }= x^{a-b} \\ \\ 
( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\ \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=$
$\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\ \\ 
 (x^{a} )^{b} = x^{a*b} \\ \\ 
\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } = \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} =$
$= \frac{8x^{3}y^{6} }{27}$

Q2. The answer is 1/16

$(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} = \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\ \\ (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } } \\ \\ 
$
$\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } = \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}$

Q3. The answer is $a^{ \frac{7}{6} }$

$a^{ \frac{2}{3} } * a^{ \frac{1}{2} } \\ \\ 
 x^{a}* x^{b} =x^{a+b} \\ \\ 
a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }$

7 0

2 years ago