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DIA [1.3K]
3 years ago
14

Barry’s dog Cubby is 1.26 meters long. Cubby is 7 times as long as Douglas’s quinea pig Taffy. How long is Taffy?

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
3 0

Answer:

taffy is 0.18 meters in length

Step-by-step explanation:

ok...so cubby is 1.26 meters long

cubby is 7 times as long as taffy

c = 1.26

c = 7t

1.26 = 7t

1.26 / 7 = t

0.18 = t

so taffy is 0.18 meters long <===

WARRIOR [948]3 years ago
3 0
Taffy is .18 meters long.
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What is the linear function equation that best fits the data set?
slavikrds [6]

Answer:

Option 3

Step-by-step explanation:

Given data set is,

{(1.5, 1), (2.5, 3), (3, 3), (3, 5), (3.5, 5), (4.5, 7), (5, 7), (5, 9), (5.5, 9), (6.5, 11), (7.5, 13)}

By using linear regression calculator,

Equation of the linear function will be,

y = 2x - 2

Therefore, Option 3 will be the correct option.

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3 years ago
Given ​f(x)=20x+11​, find ​f(4​)
kakasveta [241]

Answer:

91

Step-by-step explanation:

Substitute 4 in place of x

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3 years ago
Find the Volume for number 1 , 2 and 3
Usimov [2.4K]
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3 0
3 years ago
The height of a building is 943 feet which is about 481 feet higher than another building. What is the height of the second buil
pshichka [43]

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Step-by-step explanation:

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6 0
3 years ago
hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and
Mariulka [41]

Given:

The equation is,

2\log _3x-\log _3(x-2)=2

Explanation:

Simplify the equation by using logarthimic property.

\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{      \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}

Simplify further.

\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}

Solve the quadratic equation for x.

\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

\begin{gathered} x-6=0 \\ x=6 \end{gathered}

For (x - 3) = 0,

\begin{gathered} x-3=0 \\ x=3 \end{gathered}

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}

Equation satisfy for x = 3. So x = 3 is valid value of x.

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Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0
1 year ago
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