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nexus9112 [7]
3 years ago
12

Matt has 80,000 in a savings account. The interest rate is 12% pre year and is not compounded. How much will he have in 4 months

Mathematics
1 answer:
DENIUS [597]3 years ago
7 0
Matt will earn 3,200 interest in 4 months.

Given:
principal : 80000
interest rate : 12%
term : 4/12  *4 months in a year

Simple Interest = Principal x Interest rate x term

S.I. = 80000 x 12% x 4/12
      = 9600 x 4/12
S.I. = 3,200

OR
12% ÷ 12 month = 1% per month

S.I. = 80000 x 1% per month x 4 months
S.I. = 800 x 4 months
S.I. = 3,200
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A bowl in the shape of a hemisphere has a volume of 144π cubic centimeters. What is the radius of the bowl?
Alla [95]

Answer:

6 = r

Step-by-step explanation:

V = \frac{2}{3}πr³                Use this equation to find the volume of a hemisphere

144π = \frac{2}{3}πr³           Divide both sides by \frac{2}{3}π

216 = r³                 Take the cube root of both sides

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3 years ago
Find the distance between each pair of points E(-1, 0),F(12, 0)
Olegator [25]

Answer:

The answer is

<h2>13 \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3>d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\ </h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

E(-1, 0) and F(12, 0)

The distance between them is

<h3>|EF|  =  \sqrt{ ({ - 1 - 12})^{2}  +  ({0 - 0})^{2} }  \\  =  \sqrt{ ({ - 13})^{2} }  \\  =  \sqrt{169}</h3>

We have the final answer as

<h3>|EF| = 13 \:  \: units</h3>

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zhannawk [14.2K]

Answer:

1.) m^{15}

2.) =\frac{1}{y^{15}}

Give me a comment if you want the explanation.

1.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(m^3\right)^5=m^{3\cdot \:5}

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:5=15

=m^{15}

2.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(y^{-3}\right)^5=y^{-3\cdot \:5}

=y^{-3\cdot \:5}

=y^{-15}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

=\frac{1}{y^{15}}

4 0
3 years ago
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