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nirvana33 [79]
3 years ago
9

Find the value of x help pls

Mathematics
1 answer:
Dominik [7]3 years ago
6 0

Answer:

x = 29

Step-by-step explanation:

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Answer please if you can:))
MaRussiya [10]
I can’t see the exact numbers because the pic is blurry but here’s how to solve it.

The three angles in a triangle always add up to 180. So subtract the angle that’s given and you’ll have the sum of the two other angles. Since it’s an equilateral triangle, the other two angles are the same.
So write the equation 2(whatever the angle is) = the number you get when you do 180-the given angle

For example (I’m not sure these numbers are right because the pic is blurry)
2(9x+7)=114
Then you would solve for x and once you get x, plug it into the angle expression 9x+ 7 or whatever to get the angle measure.
5 0
2 years ago
What is another way to write the expression ​ t⋅(14−5) ​? (t⋅14)⋅5 t⋅14−5 (t⋅14)−5 (t⋅14)−(t⋅5)
Finger [1]
Another way to write the expression the answer is this (t.14)-(t.5)
5 0
3 years ago
Read 2 more answers
For the figure below the base area and the height has been provided. find the VOLUME
Inga [223]

Answer:

Step-by-step explanation:

To find the volume of this solid, multiply the base area by the height:

V = (25 cm²)(4 cm) = 100 cm³

4 0
2 years ago
The lifetimes of 10,000 watch batteries are normally distributed the mean lifetime is 500 days the standard deviation is 60 days
Lelu [443]
Given:
μ = 500 days, the population mean
σ = 60 days, the population standard deviation

Therefore
μ + σ = 560
μ - σ = 440
μ + 2σ = 620
μ - 2σ = 380
μ + 3σ = 680
μ - 3σ = 320

The figure shown below illustrates the normal distribution
About 68% of the total area lies in x = (μ-σ, μ+σ)
About 95% of the total area lies in x = (μ-2σ, μ+2σ)
About 99.7% of the total area lies in x = (μ-3σ, μ+3σ).

7 0
3 years ago
Mark bought two candy bars and a soda for $3.96. If each candy bar cost $1.10 how much did the soda cost?
stiv31 [10]

Answer:

$1.76

Step-by-step explanation:

$1.10+$1.10 = $2.2

$3.96 - $2.2 = $1.76

6 0
2 years ago
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