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Fudgin [204]
3 years ago
14

Y=-3x + 4 y= 3x - 2 Solve using Elimination Method

Mathematics
1 answer:
vova2212 [387]3 years ago
3 0

Answer:

x=1

y=1

Step-by-step explanation:

-3x+4=3x-2

-3x+3x+4=3x+3x-2

4=6x-2

4+2=6x-2+2

6=6x

x=1

y=3(1)-2

y=1

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recalling that d = rt, distance = rate * time.


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\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}


so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}


\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}

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From the options given, Dustin's hopscotch path was the longest in comparison to the other two friends.

<h3>How to find out who had the longest path?</h3>
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Based on this, let's make sure all distances are in feet.

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