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WINSTONCH [101]
2 years ago
10

Please help, this is worth 15 points!

Mathematics
2 answers:
rosijanka [135]2 years ago
5 0

Its proportional, YW!!

maxonik [38]2 years ago
4 0

Answer:

its proportional

Step-by-step explanation:

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PLEASE HELP ITS DUE TMR
sattari [20]

Answer:

it's 42 my bad...

Step-by-step explanation:

6 0
3 years ago
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The first term of a geometric series is a/b^2, and the common ratio is b/a^2. Find the next five terms of the geometric sequence
PSYCHO15rus [73]
Here it is in order (2nd to 6th):
1/ab, 1/a^3, b/a^5, b^2/a^7, b^3/a^9

Hope this helps!
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3 years ago
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Round the following factors to estimate the products
poizon [28]

Step-by-step explanation:

597 rounding would be 600 while 52 would be 50.

So 600 x 50

= 30,000

7 0
2 years ago
624 feet to 702 feet state whether the percent of the change is an increase or decrease
Ghella [55]

Answer:

The percent of change is an increase.

Step-by-step explanation:

624 has been changed to 702.

Percent change = [(Value after - Value before ) / Value before]*100

                          =\frac{702-624}{624}*100

                          =\frac{78}{624}*100

So we can clearly see that percentage change is a positive change. This means that the Value after change is higher than value before the change. So the percent of change is an increase.

8 0
3 years ago
A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the
Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

P(A) = 0.90*0.03 + 0.1*0.97 = 0.124

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

P(A \cap B) = 0.9*0.03 = 0.027

What is the conditional probability that she does, in fact, have the disease

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0
3 years ago
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