We now look at a right-angled triangle with sides a, b and c, as shown opposite. Pythagoras' Theorem states that, for any right-angled triangle, the area of the square on the hypotenuse is equal to the sum of the areas of the squares on the two shorter sides.
So we need to find the common multiples of 6 and 12. Which are basically the multiples of 12, since 6 is always divisible to 12. So (12, 24, 36, 48, 60, 72, 84, 96, 108) Since it is a factor of 108, we stop at 108 (since a number greater than 108 can't be a factor of 108)
Now we find the factors of 108
108=<span>1,2,3,4,6,9,12,18,27,36,54,108
The numbers in both lists are 36 and 108 but since Micah is thinking of a 2-digit number, the number she is thinking of is 36.</span>
Answer:
24x-15
Step-by-step explanation:
Let's do this together with a step-by-step explanation!
First we need to make sure we remember that there are appropriate ways on how to solve these. LIKE PEMDAS.
6x + 3 (2x) - 7 - 2³
Let's multiply the 3 and 2x together.
6x + 6x - 7 - 2³
Now let's do the exponent
6x + 6x - 7 - 8
Now let's add everything together! But remember only common variables can be added together.
24x - 15 is the answer.
You can no longer break anything down.
I really hope this helped you!
Is this on flvs because I'm on it also
