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3 years ago

Label each pair of triangles with the postulate or theorem that proves the triangles are congruent.

Mathematics

1 answer:

astra-53 [7]3 years ago

3 0

Answer:

We can conclude that Δ GHI ≅ Δ JKL by SAS postulate.

Step-by-step explanation:

Δ GHI and Δ JKL are congruents because:

1. Their sides GH and JK are equal (9 units = 9 units)

2. Their included angles ∠G and ∠J are equal (62° = 62°)

3. Their sides GI and JL are equal (17 units = 17 units)

Now, we can conclude that Δ GHI ≅ Δ JKL by SAS postulate.

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How do I solve <br>y=sin1/2(x+pi/4)

dexar [7]

Answer:

x = 2 csc(1) y - π/4

Step-by-step explanation:

Solve for x:

y = 1/2 sin(1) (x + π/4)

y = 1/2 (x + π/4) sin(1) is equivalent to 1/2 (x + π/4) sin(1) = y:

1/2 sin(1) (x + π/4) = y

Divide both sides by sin(1)/2:

x + π/4 = 2 csc(1) y

Subtract π/4 from both sides:

Answer: x = 2 csc(1) y - π/4

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3 years ago

It costs $20 to enter an amusement park and $0.50 to go on each ride. You have $24. How many rides are you able to go on?

zubka84 [21]

Answer:

8 rides

Step-by-step explanation:

20 + .50x = 24

-20 -20

.50x = 4

/.50 /.50

x = 8

8 0

3 years ago

Read 2 more answers

Sharon earns 4% Commission on the items that she sells one week she earns $150 in commission what is the total value of the item

Annette [7]

X = total sales
y = sharon's commision earnings

Since Sharon makes 4% of the total sales, we want to calculate how many sales equate to a $150 return. Since 4% = .04, the solution would be :

y = .04 x
150 = .04 x
150/.04 = x
3750 = x

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3 years ago

Mrs. Smythe needs 54 buttons to make costumes for the school play. Buttons come on cards of 9 buttons each. How many cards of bu

V125BC [204]

54 buttons ÷ 9 button cards = 6

She should buy 6 cards of buttons.

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3 years ago

How many roots does this has?<br>x^2+(2√5x)+2x=-10<br>find Discriminant

Alexxandr [17]

Given:

The equation is

$x^2+(2\sqrt{5})+2x=-10$

To find:

The number of roots and discriminant of the given equation.

Solution:

We have,

$x^2+(2\sqrt{5})x+2x=-10$

The highest degree of given equation is 2. So, the number of roots is also 2.

It can be written as

$x^2+(2\sqrt{5}+2)x+10=0$

Here, $a=1, b=(2\sqrt{5}+2), c=10$ .

Discriminant of the given equation is

$D=b^2-4ac$

$D=(2\sqrt{5}+2)^2-4(1)(10)$

$D=20+8\sqrt{5}+4-40$

$D=8\sqrt{5}-16$

$D\approx 1.89>0$

Since discriminant is $8\sqrt{5}-16\approx 1.89$ , which is greater than 0, therefore, the given equation has two distinct real roots.

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3 years ago