The variety of organisms within an ecosystem is characteristic of which type of diversity?

There are two main types of cell division—mitosis and meiosis. Which of the following is a true statement about the end products

Andrei [34K]

Mitosis happens in all types of cells. in this division, the cell will double it's number of chromosomes and then will be divided into two separated cells. so the number of chromosomes in product is equal to the number of chromosomes of the first cell

but meiosis only happens to produce gametes. the cell will be divided into two separated gametes.
in this division the number of chromosomes won't be doubled. so gametes have the half number of a normal person chromosomes.

good luck

3 0

3 years ago

In general, the "Y" sex chromosome does not appear to exert as much genetic influence as the "X" chromosome.

vovangra [49]

Yes. It is true.

Hope this helps!

7 0

3 years ago

You discover a new species and are given the task of describing and classifying it. Upon closer examination, you find that it ha

love history [14]

Answer:

a. Mammalia

Explanation:

Mammalia are the class species that have distinct systems and separate ducts for different activities like reproduction, excretory, and defecatory and moreover they have nipples to feed their young ones.

So, the above species which has a single duct for reproductive, excretory, and defecatory material as well as a lack of true nipples does not belong to Mammalia

4 0

3 years ago

Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from m

Vanyuwa [196]

This is an interesting problem involving astronomy, in fact, simple physics.
Let r=distance of sun to mars, in metres

Mars had an orbital period of 1.88 years.
=>
tangential velocity, v, of the planet, in m/s is
$v=\frac{2\pi{r}}{T}$
 $=\frac{2\pi{r}}{1.88*365.25*86400}$ m/s, accounting for leap years
$=3.371*10^{-8}\pi{r}$ m/s

The centripetal force, Fc, generated is
$Fc=\frac{mv^2}{r}$
where m=mass of mars = 6.39*10^(24) kg
$=\frac{mv^2}{r}$
$=\frac{6.39*10^{24}v^2}{r}$
$=7.26168*10^9\pi^2r$

The gravitation pull from the sun, Fg, is given by
$Fg=\frac{GMm}{r^2}$
where G=grav. const., =6.67408*10^(-11) m^3 kg^(-1) s^(-2)
M=mass of sun=1.989*10^(30) kg
$=\frac{6.67408*10^{-11}1.989*10^{30}6.39*10^{24}}{r^2}$
$=\frac{8.4826*10^44}{r^2}$

Since the radial distance is in equilibrium, the average distance, r can be found by equation Fc=Fg and solving for r:
Fc=Fg
=>
$7.26168*10^9\pi^2r=\frac{8.4826*10^44}{r^2}$
Solving for the real root:
$r^3=\frac{8.48256*10^44}{7.26168*10^9*%pi^2}$
$=\frac{1.1681263*10^{35}}{\pi^2}$
=2.279*10^11 m

5 0

3 years ago

What is Florida’s state freshwater fish don’t search guess

goblinko [34]

Answer:

largemouth bass

Explanation:

6 0

3 years ago

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