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Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

4 0

Answer:

-Entire triangle region : 120 sq.cm 

-Area of semi circle : 100.53 sq.cm 

-Entire composite figure : 220.53 sq.cm 

Step-by-step explanation:

Area of triangle = ½ × base × height

= ½ × (8+8) × 15

=½ × 16 × 15

= 120 sq.cm

$area \: of \: semi \: circle = \frac{1}{2} \pi {r}^{2} \\ = \frac{1}{2} \times \pi \times {8}^{2} \\ = \frac{1}{2} \times \pi \times 64 \\ = 32\pi$

=100.530.......

=100.53 sq.cm (rounded to 2 decimal place)

Area of entire figure = 120 + 100.5353

= 220.53 sq.cm

Hope I could help:))

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Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by: