we will select each options and find zeros
(a)

for finding x-intercept , we can set g(x)=0
and then we can solve for x

now, we can factor it

we get

so, this is TRUE
(b)

we can set it to 0
and then we can solve for x

we get

so, this is FALSE
(c)

we can set it to 0
and then we can solve for x




so, this is TRUE
(d)

now, we can set it to 0
and then we can solve for x


so, this is TRUE
(e)
we have

now, we can set it to 0
and then we can solve for x



so, this is FALSE
Answer:
1.f 2.a 3.j 4.e
Step-by-step explanation:
you add and subtract the needed like terms
for example you can add 3x with 4x but not with 4x² because it's a different degree
Regroup 14.1 and youll get it so easy
Answer:
The volume is 105/512 cubic inches
Step-by-step explanation:
Given [Missing from the question]
-- Length
-- Width
-- Height
Required
Determine the volume.
The volume (V) is calculated as thus:




