Answer:
Step-by-step explanation:
You are to make 5 assemblies.
Each assembly requires the use of 1 Type A bolt.
To make the 5 assemblies, you need 5 Type A bolts.
The container of bolts has a total of 60 bolts.
The focus - Type A bolts - is 20 out of this 60.
The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3
(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?
- The exact number of Type A bolts you need for the 5 assemblies is 5
1/3 × 5/10 = 5/30 = 1/6 = 0.167
(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:
1/3 × 4/10 = 0.133
1/3 × 3/10 = 0.1
1/3 × 2/10 = 0.067
1/3 × 1/10 = 0.033
1/3 × 0/10 = 0
TOTAL = 0.333
Answer: He added 4 to a negative 42 and said it was 46 but its supposed to simplify to -38. X=3/5
(6x + 8) / (4x + 4)
(3x +4) 2(x 1)
2(3x + 4) 4(x +1)
Answer:
She will thin she has 96 extra dollars.
Step-by-step explanation:
Since she recorded it as a credit she thinks that she added that to her account, and let´s say that in her account she had $100, now she has to pay $48, so in reality she has $100-$48=52, so she actually has $52 in her account, but in her checkbook she has that she had $100 and added$48, so she will have: $100+$48=$148, that a $96 deficit from her actual account to her checkbook.
1,002,003 rounded to the ten thousand place is 1,000,000
