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Shkiper50 [21]
3 years ago
5

Hi, does anyone know the answer to this question? I’m bad at geometry and I’m struggling to answer it.

Mathematics
1 answer:
vodka [1.7K]3 years ago
3 0
The answer is (2) a translation

Please Mark BRAINLIEST!
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The black graph is the graph of y=f(x). Choose the equation for the red graph.
Makovka662 [10]

Answer:

y-1 = f(x)

Step-by-step explanation:

Here, we want to choose the equation for the ref graph

The red graph as we can see is above the black

This means it is more positive

The difference between the two is just 1 unit

By the addition of 1 to the y-value of the black graph, we get the red

Thus, we have that;

y- 1 = f(x)

6 0
2 years ago
HELP!!! need answers for these questions please. Thank You for anyone who solves atleast one of them!
CaHeK987 [17]
What the other is gonna say
8 0
2 years ago
Read 2 more answers
7/8 = x/48 <br> A. 42<br> B. 6<br> C. 13<br> D. 1
Elena L [17]
7/8 = x/48

Perform cross multiplication:
a/b = c/d
ad = bc

a = 7 ; b = 8 ; c = x ; d = 48
7*48 = 8x
336 = 8x
336/8 = x
42 = x

7/8 = 42/48

42 ÷ 6 = 7
48 ÷ 6 = 8


5 0
3 years ago
Read 2 more answers
Sally Lauren is the external auditor for Modus Industries, a public company that manufactures disk drives. As she analyzes the n
ololo11 [35]

Answer:

Fictitious account receivable

Step-by-step explanation:

Fictitious account receivables involves creating fake accounts or fake sales for the purpose of having the company appear to be in a better financial condition. This can be by creating fake invoices for fake customers.

These malicious activities are carried out by employees for the purpose of having an increase in sales commission.

The quick ratio that has suddenly increased from 1.7 to 2.3 can be due to the creation of these fictitious accounts and sales.

6 0
3 years ago
Show that p must be directed through centroids of cross sections if axial stress ? is not to vary over a cross section.
wolverine [178]
Assuming P (usually written in upper case) represents a force normal to a given cross section.

If a point load is applied to any point of the section, stress concentration will cause axial stress to vary.

The context of the question considers the uniformity of axial stress at a certain distance away from the point of application (thus stress concentration can be neglected).

If a force P is applied through the centroid, sections will be stressed uniformly.  However, if the force P is applied at a distance "e" from the centroid, the equivalent load on the section equals an axial force and a moment Pe.  The latter causes bending of the member, causing non-uniform stress.

If we assume A=(uniform) cross sectional area, and I=moment of inertia of the section, then stress varies with the distance y from the centroid equal to
stress=sigma=P/A + My/I
where P=axial force, M=moment = Pe.
Therefore when e>0, the stress varies across the section.
7 0
2 years ago
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