Answer:
its B 2<-2
Step-by-step explanation:
Answer:
The simplified expression to the given expression is 
Therefore 
Step-by-step explanation:
Given fractional expression is 
To simplify the given expression as below :


( using the property
)
![=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%5B%282%29%5E4%28x%5E%7B12%7D%29%28y%5E%7B16%7D%29%5D%7D%7B%282%29%5E3%28x%5E6%29%28y%5E%7B18%7D%29%7D)
( ( using the property
)
( using the property
)
![=2[2^1x^6y^{-2}]](https://tex.z-dn.net/?f=%3D2%5B2%5E1x%5E6y%5E%7B-2%7D%5D)
( using the property
)
Therefore the simplified expression is 
Therefore 
All you have to do is divide 104 by 4! The awnser is 26
Hello,
Use the factoration
a^2 - b^2 = (a - b)(a + b)
Then,
x^2 - 81 = x^2 - 9^2
x^2 - 9^2 = ( x - 9).(x + 9)
Then,
Lim (x^2- 81) /(x+9)
= Lim (x -9)(x+9)/(x+9)
Simplity x + 9
Lim (x -9)
Now replace x = -9
Lim ( -9 -9)
Lim -18 = -18
_______________
The second method without using factorization would be to calculate the limit by the hospital rule.
Lim f(x)/g(x) = lim f(x)'/g(x)'
Where,
f(x)' and g(x)' are the derivates.
Let f(x) = x^2 -81
f(x)' = 2x + 0
f(x)' = 2x
Let g(x) = x +9
g(x)' = 1 + 0
g(x)' = 1
Then the Lim stay:
Lim (x^2 -81)/(x+9) = Lim 2x /1
Now replace x = -9
Lim 2×-9 = Lim -18
= -18