I WILL GIVE BRAINLEST IF PLEASEE HELP

Mathematics

1 answer:

goldenfox [79]3 years ago

6 0

Answer:

1. True , it doesn't change the shape

2. False , the x-axis changes

3. False , the angle will change

You might be interested in

Casey picks a bead at random from a box containing 4 red, 36 green, and 10 white beads. What is the probability that she picks 1

xxMikexx [17]

3 red 35 green 95 white

7 0

3 years ago

A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

4 0

3 years ago

Determine whether the statement is always, sometimes, or never true: Two points A and B determine a line. *

alisha [4.7K]

Answer:

sometimes

Step-by-step explanation:

8 0

3 years ago

Show work please thank you

ira [324]

1) 12 * 9 = 108 cm² - part 1
2) 12 - 3 - 3 = 6 cm
3) 6 * 4 = 24 cm² - part 2
4) 108 + 24 = 132 cm ² - the area.

3 0

3 years ago

A swim meet has 13 contestants signed up for the 100-meter butterfly event. The first heat has 6 swimmers. How many different wa

tino4ka555 [31]

Answer:

6 swimmers in the first heat can be arranged in 1716 different ways.

Step-by-step explanation:

A swim meet has 13 contestants signed up. To calculate the arrangement of first 6 swimmers in first heat we will use combinations because order doesn't matter.

So to select 6 swimmers out of 13 contestants number of different ways

= $^{13}C_{6}$