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3 years ago

14

Why is it important to study parallelograms?

1 answer:

motikmotik3 years ago

6 0

Answer:

Step-by-step explanation:

Just like any shape and/or geometry in general they are very important. Regardless of what you will ultimately study they can be used in many normal life scenarios. Since everything in our world is a shape you may need to calculate if something may fit somewhere, or if a certain fence can be made a certain way. This also applies to parallelograms, maybe you are trying to build a cabinet that will go in the corner, but the corner is not a 90 degree angle, knowing parallelograms and geometry can help you design and build the best cabinet.

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Find all solutions to the equation

tresset_1 [31]

Answer:

0,1,2,3,4,5,6.......19,20

Step-by-step explanation:

in this interval 0 is included and 21 is not included. So starting from 0 up to 20, all are the solutions

5 0

2 years ago

Amy and rob each improve thier yards by pmanting rose bushes and ivy. They brought thier supplies from the same store. Amy spent

Rzqust [24]

Answer: cost of 1 pot of ivy = $12

Cost of 1 rose bush =$ 10

Step-by-step explanation:

Step 1

Let rose bushes be represented as r

and pot of ivy be represented as p

such that Amy who spent 82 dollars on 7 rose bushes and 1 pot of ivy can be expressed as

7 r + p = 82----- eqn 1

Rob who spent 74 on 5 rose bushes and 2 pots of ivy can be expressed as

5r +2 p = 74----- eqn 2

Step 2

Solving

7 r + p = 82----- eqn 1

5r +2 p = 74----- eqn 2

By elimination method Multiply eqn 1 by 5 and eqn 2 by 7

35r+ 5p= 410--- eqn 3

35r+ 14p =518--- eqn 4

Subtracting eqn 4 from eqn 3

9p = 108

p = 108/9

p=12

p = pot of ivy = $12

therefore rose bush wll be ( from equation 1)

7r+ p= 82

7r=82-12

7r= 70 r= 70/7

r= rose bush =$ 10

5 0

3 years ago

Which two values of x are roots of the polynomial below? x^2-3x+5

Gemiola [76]

Given:

Polynomial $x^2-3x+5$

To find:

The values of x.

Solution:

$x^2-3x+5=0$

Quadratic equation formula:

$$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here $a=1, b=-3, c=5$ .

Substitute the values in the formula, we get

$$x=\frac{-(-3) \pm \sqrt{(-3)^{2}-4 \cdot 1 \cdot 5}}{2 \cdot 1}$

$$x=\frac{3 \pm \sqrt{9-20}}{2}$

$$x=\frac{3 \pm \sqrt{-11}}{2}$

$$x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}$

Option E and option F are the roots of the polynomial.

The values of x are $x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}$ .

7 0

3 years ago

Giving brainliest!!!!!!!!!!

son4ous [18]

It’s A i did the test myself..

5 0

3 years ago

6. net<br> 28 in.<br> 2.5 in.<br> Surface area

ExtremeBDS [4]

Answer:

28

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers