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snow_tiger [21]
3 years ago
15

Help me with this question

Mathematics
1 answer:
natta225 [31]3 years ago
8 0
I can’t read that so sorry I wish I could help you but I can’t bc I can’t read it
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Consider the system of equations.
Harman [31]

The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

x  = -3,  y = 2

The given system of equations:

x  +  2y  =  1............(1)

-3x - 2y  =  5..........(2)

This can be written in matrix form as shown:

\left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]

Find the determinant of \left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right]

\triangle = 1(-2) - 2(-3)\\\triangle = -2+6\\\triangle  = 4

\triangle_x = \left[\begin{array}{ccc}1&2\\5&-2\end{array}\right]\\\triangle_x = 1(-2)-2(5)\\\triangle_x = -2-10\\\triangle_x =-12

\triangle_y = \left[\begin{array}{ccc}1&1\\-3&5\end{array}\right]\\\triangle_y = 1(5)-1(-3)\\\triangle_y = 5 + 3\\\triangle_y =8

x = \frac{\triangle_x}{\triangle} \\x = \frac{-12}{4} \\x = -3

y = \frac{\triangle_y}{\triangle} \\y = \frac{8}{4} \\y = 2

The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

x  = -3,  y = 2

Learn more here: brainly.com/question/4428059

3 0
3 years ago
1 less than the square of a number.
julsineya [31]

Answer: 1 is not a perfect square. 3 is the only prime number one less than a square.

7 0
3 years ago
Help please no need for explanation
dusya [7]
It would be A=45, but i don't understand why you have a 3 above your answer
8 0
3 years ago
Read 2 more answers
2(48)+2(8w)+2(6w)=208 please explain
babymother [125]

Answer:

w=4

Step-by-step explanation:

2(48)+2(8w)+2(6w)=208

1) Start by Distributing the value outside of the parenthesis:

96+16w+12w=208

2) Combine alike terms:

96+28w=208

3) Subtract 96 from both sides:

28w=112

4)Divide both sides by 28 to isolate w:

w=4

Let me know if you do not understand :)

4 0
3 years ago
Calculate the distance between the two given point T(6,-2),U(-2,-12)
slava [35]
Use the distance formula: \sqrt{(x2 - x1)^2 + (y2 - y1)^2}

(6, -2), (-2, -12)
\sqrt{(-2 - 6)^2 + (-12 - -2)^2} ⇒ \sqrt{(-8)^2 + (-10)^2}
\sqrt{64 + 100} ⇒ \sqrt{164}
\sqrt{164} = 12.8

The distance between points T and U is 12.8 units.
3 0
3 years ago
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