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fiasKO [112]
3 years ago
14

If a = -2, b = -6, c = -4, and d = -3, evaluate the following expressions.

Mathematics
1 answer:
abruzzese [7]3 years ago
6 0
It’s Has to be B because if you had the negative numbers you get -12
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I need the answer for this problem please
Savatey [412]

Answer:

B

Step-by-step explanation:

Find all probabilities:

A. False

Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}

B. True

Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}

C. False

Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}

D. False

Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}

4 0
3 years ago
27 PTS + BRAINLIEST. I need all of these questions answered. I will award brainliest to the fastest and most correct answer. I w
erik [133]
2 Simpify:
a -4 X x = -4x
b -10 X y = -10y
c -1 X a = -a
d b X (-1) = -b
e -4 X 2m = -8m
f 6 X -3a = -18a
g -8 X -3a = 24a
h -6m X 4 = -24m
i -7 X 8n = -56n
j -a X -3 = 3a
k 6x / -2 = -3x
l -10m / -5 = 2m
m -24a / 8 = -3a
n 2(m+3)-8=2(m)+2(3)-8=2m+6-8=2m-2
o 5(m-1)+9=5(m)+5(-1)+9=5m-5+9=5m+4
p 3(a-5)+10=3(a)+3(-5)+10=3a-15+10=3a-5
q 4(2x+1)-8x=4(2x)+4(1)-8x=8x+4-8x=4
r 3(10-2x)+3x=3(10)+3(-2x)+3x=30-6x+3x=30-3x
s 4(3-x)+9x=4(3)+4(-x)+9x=12-4x+9x=12+5x

3 Simplify by collecting like terms:
a 7a-5b+2a-6b=(7+2)a+(-5-6)b=(9)a+(-11)b=9a-11b
b 11x-2y-5x+7y=(11-5)x+(-2+7)y=(6)x+(5)y=6x+5y
c 3m+2g-5g-4m=(3-4)m+(2-5)g=(-1)m+(-3)g=-m-3g
d 6a-7-9a+10=(6-9)a+(-7+10)=(-3)a+(3)=-3a+3
e 7p-2q-6p+3q=(7-6)p+(-2+3)q=(1)p+(1)q=p+q
f 3x+7-12-5x=(3-5)x+(7-12)=(-2)x+(-5)=-2x-5
g 2ab+3bc-5ab+bc=(2-5)ab+(3+1)bc=(-3)ab+(4)bc=-3ab+4bc
h 6t^2+3t-5t^2-8t=(6-5)t^2+(3-8)t=(1)t^2+(-5)t=t^2-5t
i 9y-6z-9y+5z=(9-9)y+(-6+5)z=(0)y+(-1)z=0-z=-z
j 2k-3k^2-4k+k^2=(2-4)k+(-3+1)k^2=(-2)k+(-2)k^2=-2k-2k^2
k 10t+5w+t-7w=(10+1)t+(5-7)w=(11)t+(-2)w=11t-2w
l 7a-3b-8a-5b=(7-8)a+(-3-5)b=(-1)a+(-8)b=-a-8b
8 0
3 years ago
Which of the following Triangle cases cannot be solved, using either the law of cosines or law of sines
hodyreva [135]
The answer is D. You cannot use aaa
8 0
2 years ago
Read 2 more answers
Can someone check this out to see if I have this correct? If not can you help me out please? Thank you! The answers are on 2nd p
nataly862011 [7]

Answer:

Answer 1; Angles forming a linear sum to 180°

Answer 2; Substitution

Answer 3; Definition of perpendicular lines

Step-by-step explanation:

The two column proof is presented as follows;

Statement  {}                               Reason

1. ∠SWT ≅ ∠TWU {}                    Given

2. m∠SWT + m∠TWU = 180°  {}  Angles forming a linear sum to 180°

3. m∠SWT + m∠SWT = 180° {}    Substitution

4. m∠SWT = 90°  {}                      Algebra

5. \underset{TV}{\leftrightarrow }⊥ \underset{SU}{\leftrightarrow } {}                                  Definition of perpendicular lines

Perpendicular lines are defined as lines that are at right angles (90°) to each other, therefore given that the angle formed by the lines \underset{TV}{\leftrightarrow } and \underset{SU}{\leftrightarrow } m∠SWT = 90°, therefore, the lines \underset{TV}{\leftrightarrow } and \underset{SU}{\leftrightarrow } are perpendicular to each other.

3 0
2 years ago
Adam likes to do crossword puzzle. He has a book of 200 puzzles. He has finished 95% of the puzzle in the book. How many puzzles
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190% of the book. It's simple math
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3 years ago
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