Answer:
e : g = 2 : 7
Step-by-step explanation:
e/f = 3/7
e = 3f/7
f/g = 2/3
g = 3f/2
e/g = (3f/7)/(3f/2) = 2/7
Answer:
The shape is the same
Step-by-step explanation:
we know that
A dilation is a non rigid transformation, that change the size but not the shape of the original figure
so
If the dilation scale factor is 4, the figure size increases by 4, but the shape remains the same
The solution (x,y) needs to work in both equations. With multiple choice you can do guess and test method. Otherwise you need to combine the two equations into one by substitution or elimination methods.
21. substitution works well here since one equation is y= x+3. you can easily substitute the (x+3) for y in the other equation.
2x + (x+3) = -6
3x + 3 = -6
3x = -9
x = -3
use this in either equation to find y.
y = (-3)+3
solution: (-3,0)
22. these both equal y so they equal each other.
4x - 1 = 3x +6
4x - 3x = 6 + 1
x = 7
use this in either equation to find y
y = 4(7) - 1
y = 28 - 1
y = 27
solution: (7,27)
23. one equation is y = 2x - 3. So substitute (2x -3) for y in the other equation.
4x = 2(2x - 3) + 6
4x = 4x - 6 + 6
4x = 4x
x = x
any solution will work, infinitely many.
24. infinitely many solutions means the two equations are the same equation. Like the previous one they didn't look the same but if you put them both in terms of y...
y= 2x-3
4x = 2y + 6
4x - 6 = 2y
(4x - 6)/2 = y
2x - 3 = y
same equation.
from the image, I can't see all options but A & C do not look like the same equations. It's got to be either B or D.
Answer:
There are Even, Odd and None of them and this does not depend on the degree but on the relation. An Even function: 
And Odd one: 
Step-by-step explanation:
1) Firstly let's remember the definition of Even and Odd function.
An Even function satisfies this relation:
An Odd function satisfies that:
2) <u>Since no function has been given</u>. let's choose some nonlinear functions and test with respect to their degree:
3) Then these functions are respectively even and odd, because they passed on the test for even and odd functions namely, and 
for odd functions.
Since we need to have symmetry to y axis to Even functions, and Symmetry to Odd functions, and moreover, there are cases of not even or odd functions we must test each one case by case.
Answer: i think method of least squares (d.)
Step-by-step explanation: i’m pretty sure this is correct because mean is good for unimodal, unskewed histograms, median is good for unimodal asymmetrical histograms, and mode is good for bimodal histograms. i’m not sure tho bcs i learned this in statistics.
