Answer:
10
Step-by-step explanation:
<span>After 1 hour, the diving bell was -1/2 mile relative to sea level.
Since the rate of decent is constant, we can use two ratios to represent the depth at 2 different times. To make things easier to write, I'll use decimals to represent time and depth.
-.75 / 1.5 = x / 1
Now solve for x
-0.5 = x
So after 1 hour, the diving bell was -1/2 mile relative to sea level.</span>
Answer:
Therefore,
Correct options are
A) 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
D) 2 × 100 + 6 × 1/100
Step-by-step explanation:
Given:
Number is
200.06
For option A)
2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
= 200 + 0 + 0 + 0.06
= 200.06
Which is CORRECT.
For option B)
2 × 100 + 0 × 1 + 0 × 1/100 + 6 × 1/1,000
= 200 + 0 + 0 + 0.006
=200.006
Which is INCORRECT.
For option C)
2 × 100 + 6 × 1/10
= 200 + 0.6
= 200.6
Which is INCORRECT.
For option D)
2 × 100 + 6 × 1/100
= 200 + 0.06
= 200.06
Which is CORRECT.
Therefore,
Correct options are
A) 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100
D) 2 × 100 + 6 × 1/100
3/4 would be a fraction, equivalent to 6/8.
Answer:
a) 0.125
b) 7
c) 0.875 hr
d) 1 hr
e) 0.875
Step-by-step explanation:l
Given:
Arrival rate, λ = 7
Service rate, μ = 8
a) probability that no requests for assistance are in the system (system is idle).
Let's first find p.
a) ρ = λ/μ
Probability that the system is idle =
1 - p
= 1 - 0.875
=0.125
probability that no requests for assistance are in the system is 0.125
b) average number of requests that will be waiting for service will be given as:
λ/(μ - λ)
= 7
(c) Average time in minutes before service
= λ/[μ(μ - λ)]
= 0.875 hour
(d) average time at the reference desk in minutes.
Average time in the system js given as: 1/(μ - λ)
= 1 hour
(e) Probability that a new arrival has to wait for service will be:
λ/μ =
= 0.875
