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3 years ago

One pretzel has 20 calories. Write an algebraic expression for the total number of calories in n pretzels.

Mathematics

1 answer:

vredina [299]3 years ago

4 0

Answer:

20n

Step-by-step explanation:

One pretzel has 20 calories. Write an algebraic expression for the total number of calories in n pretzels.

1 pretzel = 20 calories

n pretzel = x

Cross Multiply

x × 1 pretzel = n pretzel × 20 calories

x = n pretzel × 20 calories/1 pretzel

x = 20 n

Therefore, an algebraic expression for the total number of calories in n pretzels = 20n

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4 x ((-4)= (-2) - (-3) + (-6))

sergij07 [2.7K]

Answer:

x=5/16

Step-by-step explanation:

Let's solve your equation step-by-step.

4x(−4)=−2−(−3)−6

Step 1: Simplify both sides of the equation.

4x(−4)=−2−(−3)−6

−16x=−2+3+−6

−16x=(−2+3+−6)(Combine Like Terms)

−16x=−5

Step 2: Divide both sides by -16.

−16x

−16

=−5/−16

x=5/16

can I be the brainiest please!!

4 0

3 years ago

Can someone please do this for me please please i did the top but i dont get these so please

svlad2 [7]

I belive what you have to do is substitute the x with the numver given on the left, so the first one would be -3-13 which is -16, so then that means y= -16 , so the ordered pair would be (-3,-16)
Hope this helps!!

4 0

3 years ago

Could someone help with my previously asked questions

m_a_m_a [10]

Answer:

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Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]

I'll use subscript notation for brevity, i.e. $\frac{\partial f}{\partial x}=f_x$ .

By the chain rule,

$z_u=z_xx_u+z_yy_u$

$z_v=z_xx_v+z_yy_v$

$z_w=z_xx_w+z_yy_w$

We have

$z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}$

and

$\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}$

When $u=1,v=1,w=0$ , we have

$\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}$

and the partial derivatives take on values of

$\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}$

So we end up with

$\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}$

3 0

3 years ago

What is the slope of the line that passes through (-3,-2) and (3,-1) Give your answer as a fraction

svlad2 [7]

Using slope formula, the slope will be 1/6

7 0

3 years ago